Hi phoenixio,

Well the mean is given to be 75. Let the integers be x,y,z, 90.

So we know that:

\(\frac{(x+y+z+90)}{4}\)= 75

\(x+y+z= 210\)

Lets say z is the smallest. So in order for z to be smallest possible x and y should be largest values possible.

Now we also know that \(x,y,z < 90\) (since 90 is the largest integer) and x,y,z, 90 are "different".

So x = 89 and y= 88 satisfy this criteria:

Hence \(z = 210 - 89 -88 =33\).

Cheers

PS: Source of the Que ?

_________________

Sandy

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