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The average (arithmetic mean) of 12 and 20 is equal to the a

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The average (arithmetic mean) of 12 and 20 is equal to the a [#permalink]  14 May 2018, 12:13
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84% (00:24) correct 15% (00:21) wrong based on 38 sessions
The average (arithmetic mean) of 12 and 20 is equal to the average (arithmetic mean) of 15 and x.

 Quantity A Quantity B x 16

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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WE: Engineering (Energy and Utilities)
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Re: The average (arithmetic mean) of 12 and 20 is equal to the a [#permalink]  03 Aug 2018, 21:52
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Carcass wrote:
The average (arithmetic mean) of 12 and 20 is equal to the average (arithmetic mean) of 15 and x.

 Quantity A Quantity B x 16

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

From the statement we can write as:

$$\frac{12 + 20}2 = \frac{15 + x}2$$

or $$x = 12 + 5 = 17$$

QTY A > QTY B
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Re: The average (arithmetic mean) of 12 and 20 is equal to the a [#permalink]  01 Oct 2019, 09:14
Expert's post
Carcass wrote:
The average (arithmetic mean) of 12 and 20 is equal to the average (arithmetic mean) of 15 and x.

 Quantity A Quantity B x 16

Given: The average (arithmetic mean) of 12 and 20 is equal to the average (arithmetic mean) of 15 and x

We can write: $$\frac{12+20}{2} = \frac{15+x}{2}$$

Multiply both sides by 2 to get: $$12+20 = 15+x$$

Simplify to get: $$32 = 15+x$$

Solve: $$x = 17$$

we get:
Quantity A: 17
Quantity B: 16

Answer: A

Cheers,
Brent
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Re: The average (arithmetic mean) of 12 and 20 is equal to the a   [#permalink] 01 Oct 2019, 09:14
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