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The average (arithmetic mean) of 10 numbers is 52 . When one
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11 Mar 2020, 11:02
11 Mar 2020, 11:02
Expert Reply
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The average (arithmetic mean) of 10 numbers is 52 . When one of the numbers is discarded, the average of the remaining numbers becomes 53.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The discarded number |
51 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
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Re: The average (arithmetic mean) of 10 numbers is 52 . When one
[#permalink]
11 Mar 2020, 11:09
11 Mar 2020, 11:09
3
Carcass wrote:
The average (arithmetic mean) of 10 numbers is 52 . When one of the numbers is discarded, the average of the remaining numbers becomes 53.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The discarded number |
51 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Sum of the 10 numbers = 10 * 52 = 520
After removing one number:
Sum of the 9 numbers = 9 * 53 = 477
=> Value of the discarded number = 520 - 477 = 43
=> Quantity B is greater
Answer B
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Re: The average (arithmetic mean) of 10 numbers is 52 . When one
[#permalink]
06 Apr 2020, 13:16
06 Apr 2020, 13:16
i used the calculator for this one, how about ya?
The average (arithmetic mean) of 10 numbers is 52 . When one
[#permalink]
14 Feb 2021, 11:46
14 Feb 2021, 11:46
Expert Reply
Carcass wrote:
The average (arithmetic mean) of 10 numbers is 52 . When one of the numbers is discarded, the average of the remaining numbers becomes 53.
Quantity A |
Quantity B |
The discarded number |
51 |
The average (arithmetic mean) of 10 numbers is 52
We can write: (sum of all 10 numbers)/10 = 52
Multiply both sides of the equation by 10 to get: sum of all 10 numbers = 520
When one of the numbers is discarded, the average of the remaining numbers becomes 53
Once a number is discarded. there are 9 numbers remaining.
So, we can write: (sum of the remaining 9 numbers)/9 = 53
Multiply both sides of the equation by 9 to get: sum of the remaining 9 numbers = 477
520 - 477 = 43
So, 43 must be the number that was discarded.
We have:
QUANTITY A: 43
QUANTITY B: 51
Answer: B
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