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# The average (arithmetic mean) cost per hinge for 16 hinges t

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GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4810
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 117

Kudos [?]: 1895 [0], given: 397

The average (arithmetic mean) cost per hinge for 16 hinges t [#permalink]  22 Nov 2017, 19:09
Expert's post
00:00

Question Stats:

67% (00:32) correct 32% (00:30) wrong based on 28 sessions
 Quantity A Quantity B The average (arithmetic mean) cost per hinge for 16 hinges that cost a total of 2p cents The average (arithmetic mean) cost per hinge for 4 hinges that cost a total of $$\frac{p}{2}$$ cents

A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.

Drill 2
Question: 10
Page: 526
[Reveal] Spoiler: OA

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Manager
Joined: 25 Nov 2017
Posts: 51
Followers: 0

Kudos [?]: 43 [1] , given: 5

Re: The average (arithmetic mean) cost per hinge for 16 hinges t [#permalink]  08 Dec 2017, 06:57
1
KUDOS
Hi,

For QA
Cost per hinge is as follows
16/2p which is 8/p

For QB
Cost per hinge is 4/p÷2 which is 8/p

So C
GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4810
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 117

Kudos [?]: 1895 [0], given: 397

Re: The average (arithmetic mean) cost per hinge for 16 hinges t [#permalink]  29 Dec 2017, 14:06
Expert's post
Explanation

Plug in a value for p. Try p = 16: In Quantity A, then 16 hinges cost a total of 32 cents, for an average cost of 2 cents per hinge; in Quantity B, 4 hinges cost a total of 8 cents, for, again, an average cost of 2 cents per hinge.

The quantities are equal, so eliminate choices (A) and (B). Any value for p will yield the same results: The quantities will always equal; the

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Sandy
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Re: The average (arithmetic mean) cost per hinge for 16 hinges t   [#permalink] 29 Dec 2017, 14:06
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