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# The “aspect ratio” of a computer monitor is the ratio of the

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Retired Moderator
Joined: 07 Jun 2014
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The “aspect ratio” of a computer monitor is the ratio of the [#permalink]  14 Jun 2018, 14:11
Expert's post
00:00

Question Stats:

50% (00:40) correct 50% (00:57) wrong based on 26 sessions
The “aspect ratio” of a computer monitor is the ratio of the monitor’s width to its height. If a particular monitor has an aspect ratio of 16 : 9, and a perimeter of 100 inches, how many inches wide is the monitor?

(A) 18
(B) 25
(C) 32
(D) 36
(E) 64
[Reveal] Spoiler: OA

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Sandy
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Retired Moderator
Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 173

Kudos [?]: 2977 [0], given: 394

Re: The “aspect ratio” of a computer monitor is the ratio of the [#permalink]  05 Jul 2018, 01:44
Expert's post
Explanation

Rather than assigning separate variables to the width and height, define them both in terms of the same unknown multiplier, based on the ratio given:

Width = 16m

Height = 9m

Remember that the question asks for the width, so answer for 16m, not for m!

The perimeter of a rectangle is equal to 2(length + width), or in this case 2(width + height):

$$100 = 2 \times (16m + 9m)$$

$$100 = 50m$$

$$m = 2$$

$$16m = 32$$

An alternative method depends on the same underlying logic, but forgoes the algebra. Suppose the dimensions were 16 inches and 9 inches. This would yield a perimeter of 50 inches. Double the width and height to double the perimeter.

Hence option C is correct!
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Sandy
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Re: The “aspect ratio” of a computer monitor is the ratio of the   [#permalink] 05 Jul 2018, 01:44
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