Triangle ABC is a isosceles right-angled triangle.A = C = 45 degrees.Therefore, AB = BC = Sq.root(2)

Area of triangle ABC = 1/2 * Sq.root(2) * Sq.root(2)
= 1/2 * 2
= 1

In Triangle DEF , angle F= 30 degrees.

Sin 30 = 1/2 =DE/2

DE = 1

Also, Cos 30 = Sq.root(3)/2 = EF/2

EF = Sq.root(3) = 1.732

This implies area of triangle DEF = 1/2 * 1 * 1.732
= .866

Clearly,Area of ABC is greater than Area of DEF.