Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

The area of a circular region having a radius of 41 meter is [#permalink]
14 Jun 2018, 16:08

Expert's post

00:00

Question Stats:

79% (00:54) correct
20% (00:57) wrong based on 29 sessions

The area of a circular region having a radius of \(\frac{1}{4}\) meter is x square meters.

Quantity A

Quantity B

\(x\)

\(\frac{1}{4}\)

A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.

Re: The area of a circular region having a radius of 41 meter is [#permalink]
15 Jun 2018, 05:58

1

This post received KUDOS

Carcass wrote:

The area of a circular region having a radius of \(\frac{1}{4}\) meter is x square meters.

Quantity A

Quantity B

\(x\)

\(\frac{1}{4}\)

A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.

Re: The area of a circular region having a radius of 41 meter is [#permalink]
17 Jun 2018, 07:37

1

This post received KUDOS

Expert's post

Carcass wrote:

The area of a circular region having a radius of \(\frac{1}{4}\) meter is x square meters.

Quantity A

Quantity B

\(x\)

\(\frac{1}{4}\)

A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.

Area of circle = π(radius)²

So, if the radius is 1/4, then area = π(1/4)² = π(1/16) = π/16

In other words, x = π/16

So, we get: Quantity A: π/16 Quantity B: 1/4

If we're not sure what to do here, a quick approach is to use matching operations

Multiply both quantities by 16 to get: Quantity A: π Quantity B: 4

Since π ≈ 3.14, we can see that Quantity B is greater.

Answer: B

RELATED VIDEO FROM OUR COURSE

_________________

Brent Hanneson – Creator of greenlighttestprep.com Sign up for my free GRE Question of the Dayemails