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The area of

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Founder
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The area of [#permalink] New post 09 Jun 2018, 08:37
Expert's post
00:00

Question Stats:

91% (00:24) correct 8% (01:11) wrong based on 23 sessions
Attachment:
#GREpracticequestion The area of triangle OPQ.jpg
#GREpracticequestion The area of triangle OPQ.jpg [ 14.44 KiB | Viewed 649 times ]


The area of \(\Delta OPQ\) is the figure above is

A. 6

B. 12

C. 14

D. 21

E. 42
[Reveal] Spoiler: OA

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Re: The area of [#permalink] New post 09 Jun 2018, 11:17
Carcass wrote:
Attachment:
triangle.jpg


The area of \Delta OPQ is the figure above is

A. 6

B. 12

C. 14

D. 21

E. 42


Simplest formula , when triangle has (0,0) as its one of its vertices then other two sides (a,b) and (c,d) are considered.

In our case ( 2,7 ) as (a,b) and (6,0) as (c,d).

then formula for triangle area is = |ad - bc | / 2 => | 0 - 42 | / 2 => 21.

Option D.
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Re: The area of [#permalink] New post 09 Jun 2018, 11:21
Expert's post
Elegant solution but you waste time during the exam, performing such process. However, it is not wrong at all, though.

\(A= \frac{b*h}{2}\)

\(\frac{7*6}{2} = \frac{42}{2} = 21\)

D is the answer
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Re: The area of   [#permalink] 09 Jun 2018, 11:21
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