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Team X scored p points more than Team Y

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Team X scored p points more than Team Y [#permalink] New post 18 Mar 2018, 11:23
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Team X scored p points more than Team Y, and the two teams together scored a total of 10 points.

Quantity A
Quantity B
Twice the number of points team Y scored
10 - p


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: Team X scored p points more than Team Y [#permalink] New post 18 Mar 2018, 14:04
Can someone explain why the answer is C?
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Re: Team X scored p points more than Team Y [#permalink] New post 18 Mar 2018, 20:31
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Explanation

Let us assume team Y scored \(a\) number of points
From question we get Team x points to be \(a + p\)
Total point would then be \(a + a + p = 2a + p\)
Also, from question we know that \(2a + p = 10\)

Now twice the number of points team Y scored would be \(2a\)

Quantity \(B = 10 - p\); we have derived \(2a + p =10\) so replace \(2a + 10\) in place of 10
we get, \(B = 2a + p - p = 2a\)
Qnty A = Qnty B
option C
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Re: Team X scored p points more than Team Y [#permalink] New post 18 Mar 2018, 23:40
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X scored p more points than Y: X - Y = P

Two two teams together scored a total of 10 points: X + Y = 10

A: 2Y

B: 10 - p

Solve the two equations above by summing and eliminating Y. We get X = (10 + P) / 2

Substitute away the value of X in either of the two equations to solve for Y: Y = 10 - X --> Y = 10 - ((10 + P)/2)

Multiply by 2 to get 2Y = 10 - P.

So Ans: C.
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Re: Team X scored p points more than Team Y [#permalink] New post 19 Mar 2018, 16:17
answer: C
Team X scored p points more than Team Y, and the two teams together scored a total of 10 points.
Twice the number of points team Y scored
10 - p
score_x = p + score_y
score_x + score_y = 10
p + score_y +score_y = p + 2* score_y = 10 so 2 * score_y = 10 - p
so both A and B are equal. and the answer is C.
Re: Team X scored p points more than Team Y   [#permalink] 19 Mar 2018, 16:17
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