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# Tarik has a pile of 6 green chips numbered 1 through 6 respe

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Retired Moderator
Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 175

Kudos [?]: 3033 [1] , given: 394

Tarik has a pile of 6 green chips numbered 1 through 6 respe [#permalink]  05 Aug 2018, 14:40
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Expert's post
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Question Stats:

80% (00:46) correct 19% (00:19) wrong based on 98 sessions
Tarik has a pile of 6 green chips numbered 1 through 6 respectively and another pile of 6 blue chips numbered 1 through 6 respectively. Tarik will randomly pick 1 chip from
the green pile and 1 chip from the blue pile.

 Quantity A Quantity B The probability that both chips selected by Tarik will display a number less than 4. $$\frac{1}{2}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Sandy
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Retired Moderator
Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 175

Kudos [?]: 3033 [0], given: 394

Re: Tarik has a pile of 6 green chips numbered 1 through 6 respe [#permalink]  07 Aug 2018, 06:22
Expert's post
Explanation

In this problem, Tarik is not picking 1 chip out of all 12. Rather, he is picking 1 chip out of 6 green ones, and then picking another chip out of 6 blue ones. There are 3 green chips with numbers less than 4, so Tarik has a $$\frac{3}{6}$$ chance of selecting a green chip showing a number less than 4.

Likewise, Tarik has a $$\frac{3}{6}$$ chance of selecting a blue chip showing a number less than 4.

Therefore, Quantity A is equal to $$\frac{3}{6}\times \frac{3}{6}=\frac{1}{2}\times\frac{1}{2}=\frac{1}{4}$$. Quantity B is greater.
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Sandy
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Manager
Joined: 22 Feb 2018
Posts: 163
Followers: 2

Kudos [?]: 139 [2] , given: 22

Re: Tarik has a pile of 6 green chips numbered 1 through 6 respe [#permalink]  02 Jan 2019, 18:26
2
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6 green chips, 1 to 6
6 blue chips, 1 to 6
Randomly 1 from greens and randomly one from blue
A: The probability that both chips will display a number less than 4: P(greens <4 and blues <4) = P(greens <4) * P(blues <4) = 3/6 * 3/6 = 1/4
B: 1/2

B is greater than A and the answer is B.
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Manager
Joined: 22 Aug 2019
Posts: 72
Followers: 1

Kudos [?]: 51 [0], given: 11

Re: Tarik has a pile of 6 green chips numbered 1 through 6 respe [#permalink]  09 Sep 2019, 18:58
sandy wrote:
Tarik has a pile of 6 green chips numbered 1 through 6 respectively and another pile of 6 blue chips numbered 1 through 6 respectively. Tarik will randomly pick 1 chip from
the green pile and 1 chip from the blue pile.

 Quantity A Quantity B The probability that both chips selected by Tarik will display a number less than 4. $$\frac{1}{2}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Quick way to do this problem:

Clearly, there is a 3/6 chance that one of the cookies selected will satisfy the criteria. Pulling that off twice in a row? 1/4. Clearly B is larger than A.
Re: Tarik has a pile of 6 green chips numbered 1 through 6 respe   [#permalink] 09 Sep 2019, 18:58
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# Tarik has a pile of 6 green chips numbered 1 through 6 respe

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