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# t > 1

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Founder
Joined: 18 Apr 2015
Posts: 9746
Followers: 202

Kudos [?]: 2386 [0], given: 9231

t > 1 [#permalink]  19 Jul 2019, 09:03
Expert's post
00:00

Question Stats:

87% (00:39) correct 12% (00:49) wrong based on 32 sessions
$$t > 1$$

 Quantity A Quantity B $$\frac{2t+5}{3}$$ $$3t$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
[Reveal] Spoiler: OA

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Moderator
Joined: 03 Apr 2019
Posts: 196
Followers: 2

Kudos [?]: 156 [1] , given: 2

Re: t > 1 [#permalink]  08 Sep 2019, 21:51
1
KUDOS
t>1, so lets assume t = 2
Qty A: (2(2)+5)/3= 9/3=3
Qty B: 3(2) = 6
In this case, Qty B is greater.
Lets assume t = 1.1
QTY A: (2.2+5)/3= 7.2/3=2.4
Qty B: 3.3
So, in all the cases, Qty B is greater.
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GRE Instructor
Joined: 10 Apr 2015
Posts: 2821
Followers: 106

Kudos [?]: 3129 [3] , given: 54

Re: t > 1 [#permalink]  10 Sep 2019, 10:23
3
KUDOS
Expert's post
Carcass wrote:
$$t > 1$$

 Quantity A Quantity B $$\frac{2t+5}{3}$$ $$3t$$

We can solve this question using matching operations

Given:
Quantity A: $$\frac{2t+5}{3}$$

Quantity B: $$3t$$

Multiply both quantities by 3 to get:
Quantity A: $$2t+5$$

Quantity B: $$9t$$

Subtract 2t from both quantities to get:
Quantity A: $$5$$

Quantity B: $$7t$$

Divide both quantities by 7 to get:
Quantity A: $$\frac{5}{7}$$

Quantity B: $$t$$

Since we're told $$t > 1$$, we know that $$t>\frac{5}{7}$$

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Re: t > 1   [#permalink] 10 Sep 2019, 10:23
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