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Moderator  Joined: 18 Apr 2015
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Expert's post 00:00

Question Stats: 68% (01:16) correct 31% (01:39) wrong based on 19 sessions
$$\sqrt{96} < x \sqrt{6}$$ and $$\frac{x}{\sqrt{6}}$$ $$< \sqrt{6}$$. If x is an integer, which of the following is the value of x?

(A) 2

(B) 3

(C) 4

(D) 5

(E) 6
[Reveal] Spoiler: OA

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Director Joined: 20 Apr 2016
Posts: 826
WE: Engineering (Energy and Utilities)
Followers: 11

Kudos [?]: 603 , given: 124

Carcass wrote:
$$\sqrt96 < x \sqrt6$$ and $$\frac{x}{\sqrt{6}}$$ $$< \sqrt{6}$$. If x is an integer, which of the following is the value of x?

(A) 2

(B) 3

(C) 4

(D) 5

(E) 6

$$\sqrt96 < x \sqrt6$$

or $$4\sqrt6 < x \sqrt6$$

or$$4 < x$$

From the 2nd statement,

$${\frac{x}{\sqrt{6}}} < \sqrt6$$

or $$x < \sqrt6 * \sqrt6$$

or$$x < 6$$

So the value of x lies between $$4 < x < 6$$

So the answer is D i.e. 5
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