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Founder  Joined: 18 Apr 2015
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Expert's post 00:00

Question Stats: 77% (01:09) correct 22% (01:18) wrong based on 59 sessions
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Carcass wrote:
$$\sqrt96 < x \sqrt6$$ and $$\frac{x}{\sqrt{6}}$$ $$< \sqrt{6}$$. If x is an integer, which of the following is the value of x?

(A) 2

(B) 3

(C) 4

(D) 5

(E) 6

$$\sqrt96 < x \sqrt6$$

or $$4\sqrt6 < x \sqrt6$$

or$$4 < x$$

From the 2nd statement,

$${\frac{x}{\sqrt{6}}} < \sqrt6$$

or $$x < \sqrt6 * \sqrt6$$

or$$x < 6$$

So the value of x lies between $$4 < x < 6$$

So the answer is D i.e. 5
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GRE Prep Club Members of the Month:TOP 10 members of the month with highest kudos receive access to 3 months GRE Prep Club tests Re: sqrt96<x<sqrt6   [#permalink] 12 Aug 2018, 01:08
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