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# \sqrt8/\sqrt2

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\sqrt8/\sqrt2 [#permalink]  13 Jun 2018, 12:57
Expert's post
00:00

Question Stats:

89% (00:16) correct 10% (00:21) wrong based on 46 sessions
 Quantity A Quantity B $$\frac{\sqrt{8}}{\sqrt{2}}$$ $$\frac{\sqrt{12}}{\sqrt{3}}$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Intern
Joined: 21 Nov 2017
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Kudos [?]: 17 [1] , given: 0

Re: \sqrt8/\sqrt2 [#permalink]  13 Jun 2018, 17:51
1
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Quantity A = (8/2)^(1/2) = 4^(1/2)
Quantity B = (12/3)^(1/2) = 4^(1/2)
--> A = B

Keys: C
GRE Instructor
Joined: 10 Apr 2015
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Kudos [?]: 4490 [1] , given: 69

Re: \sqrt8/\sqrt2 [#permalink]  14 May 2020, 06:10
1
KUDOS
Expert's post
Carcass wrote:
 Quantity A Quantity B $$\frac{\sqrt{8}}{\sqrt{2}}$$ $$\frac{\sqrt{12}}{\sqrt{3}}$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Key concept: $$\frac{\sqrt{x}}{\sqrt{y}}=\sqrt{\frac{x}{y}}$$

For example, $$\frac{\sqrt{36}}{\sqrt{4}}=\sqrt{\frac{36}{4}}=\sqrt{9}=3$$

We get:
Quantity A: $$\frac{\sqrt{8}}{\sqrt{2}}=\sqrt{\frac{8}{2}}=\sqrt{4}=2$$

Quantity B: $$\frac{\sqrt{12}}{\sqrt{3}}=\sqrt{\frac{12}{3}}=\sqrt{4}=2$$

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
If you enjoy my solutions, you'll like my GRE prep course.

Re: \sqrt8/\sqrt2   [#permalink] 14 May 2020, 06:10
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