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# \sqrt12.5 + \sqrt12.5

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Founder
Joined: 18 Apr 2015
Posts: 7791
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Kudos [?]: 1597 [0], given: 7061

\sqrt12.5 + \sqrt12.5 [#permalink]  16 Apr 2019, 01:28
Expert's post
00:00

Question Stats:

50% (00:12) correct 50% (00:00) wrong based on 8 sessions
 Quantity A Quantity B $$\sqrt{12.5} + \sqrt{12.5}$$ $$\sqrt{25}$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________
GRE Instructor
Joined: 10 Apr 2015
Posts: 2311
Followers: 72

Kudos [?]: 2200 [1] , given: 27

Re: \sqrt12.5 + \sqrt12.5 [#permalink]  16 Apr 2019, 05:33
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Expert's post
Carcass wrote:
 Quantity A Quantity B $$\sqrt{12.5} + \sqrt{12.5}$$ $$\sqrt{25}$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

√9 = 3
√16 = 4

Since 12.5 is BETWEEN 9 and 16, √12.5 must be between 3 and 4
We can say that √12.5 = 3.something

We get:
QUANTITY A: 3.something + 3.something
QUANTITY B: 5

We can see that Quantity A is greater.

Answer: A

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com

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Intern
Joined: 28 Apr 2019
Posts: 24
Followers: 0

Kudos [?]: 9 [1] , given: 4

Re: \sqrt12.5 + \sqrt12.5 [#permalink]  02 May 2019, 01:41
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The solution given is wrong as it is clearly evident that the A= 2*sqrt(12.5) which is 7 and B=5.
The answer should be A.
Founder
Joined: 18 Apr 2015
Posts: 7791
Followers: 145

Kudos [?]: 1597 [0], given: 7061

Re: \sqrt12.5 + \sqrt12.5 [#permalink]  02 May 2019, 01:56
Expert's post
Fixed. There was a typo in the book.

Thank you so much
_________________
Re: \sqrt12.5 + \sqrt12.5   [#permalink] 02 May 2019, 01:56
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# \sqrt12.5 + \sqrt12.5

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