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\sqrt100+36

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\sqrt100+36 [#permalink] New post 13 May 2018, 15:07
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Question Stats:

87% (00:17) correct 12% (00:21) wrong based on 31 sessions
Quantity A
Quantity B
\(\sqrt{100+36}\)
\(16\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: \sqrt100+36 [#permalink] New post 03 Aug 2018, 21:50
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Carcass wrote:
Quantity A
Quantity B
\(\sqrt{100+36}\)
\(16\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.



QTY A = \(\sqrt{100+36} = \sqrt{136}\) = That lies between 11 and 12 (Because \(\sqrt{121} = 11\) and \(\sqrt{144} = 12\))

So QTY A < QTY B
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Re: \sqrt100+36 [#permalink] New post 02 Jan 2020, 20:49
Simply square both sides. Left side will be (100+36) = 136 and Right side will be 16*16 = 256. Correct ans is B.
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Re: \sqrt100+36 [#permalink] New post 02 Jan 2020, 22:12
\(16^2\) = 256
A says \(\sqrt{100+36}\) = \(\sqrt{136}\) < \(\sqrt{256}\)

Hence, B
Carcass wrote:
Quantity A
Quantity B
\(\sqrt{100+36}\)
\(16\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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Re: \sqrt100+36   [#permalink] 02 Jan 2020, 22:12
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\sqrt100+36

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