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# \sqrt 4r=6

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Intern
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\sqrt 4r=6 [#permalink]  22 Aug 2019, 02:55
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Question Stats:

81% (00:18) correct 18% (00:36) wrong based on 11 sessions
 Quantity A Quantity B $$\sqrt{4r}=6$$ $$s^2=81$$

A)Quantity A is greater.
B)Quantity B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
[Reveal] Spoiler: OA
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Re: \sqrt 4r=6 [#permalink]  22 Aug 2019, 03:58
Expert's post
A) $$( \sqrt{4r} = 6 )^2$$; $$4r = 36$$ ; $$r = 9$$

B) $$s = \pm 9$$;

$$A = B$$ if we consider positive 9

$$A > B$$ if we consider in quantity A 9 and in quantity B -9

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Intern
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Re: \sqrt 4r=6 [#permalink]  25 Aug 2019, 06:50
Quantity A comes out to be 9
Quantity B gives to values 9 and -9
Re: \sqrt 4r=6   [#permalink] 25 Aug 2019, 06:50
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