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# Solution X is 10 percent alcohol by volume, and solution Y

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Senior Manager
Joined: 20 May 2014
Posts: 282
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Kudos [?]: 49 [0], given: 220

Solution X is 10 percent alcohol by volume, and solution Y [#permalink]  26 Oct 2017, 02:33
00:00

Question Stats:

100% (02:05) correct 0% (00:00) wrong based on 3 sessions
Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 25 percent alcohol by volume?

A. 250/3
B. 500/3
C. 400
D. 480
E. 600

Kudos for correct solution.
[Reveal] Spoiler: OA
Director
Joined: 03 Sep 2017
Posts: 521
Followers: 1

Kudos [?]: 327 [0], given: 66

Re: Solution X is 10 percent alcohol by volume, and solution Y [#permalink]  26 Oct 2017, 04:44
The problem can be solved using the formula for the weighted average as $$\frac{200*0.10+x*0.3}{200+x} = 0.25$$, where x is the amount of solution Y needed to reach a 25% concentration in the mix. Solving, we get x = 600 thus answer E
Re: Solution X is 10 percent alcohol by volume, and solution Y   [#permalink] 26 Oct 2017, 04:44
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# Solution X is 10 percent alcohol by volume, and solution Y

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