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Six beads, each a different color, are put into a bag. How

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Senior Manager
Joined: 20 May 2014
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Six beads, each a different color, are put into a bag. How [#permalink]  19 Oct 2017, 01:19
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Six beads, each a different color, are put into a bag. How many different three-color combinations are possible if 3 beads are drawn out of the bag simultaneously? (Assume the order of the colors does not matter.)

(A) 6
(B) 9
(C) 18
(D) 20
(E) 120

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[Reveal] Spoiler: OA
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Joined: 03 Sep 2017
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Kudos [?]: 334 [1] , given: 66

Re: Six beads, each a different color, are put into a bag. How [#permalink]  19 Oct 2017, 01:30
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Since the order does not matter we are talking about combinations. Then, the problem is solved by computing $$\frac{6!}{3!3!} = \frac{6*5*4}{2*3} = 20$$.

Re: Six beads, each a different color, are put into a bag. How   [#permalink] 19 Oct 2017, 01:30
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