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# Set T consists of all multiples of 5 from 30 to 225 inclusiv

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Senior Manager
Joined: 20 May 2014
Posts: 282
Followers: 18

Kudos [?]: 50 [0], given: 220

Set T consists of all multiples of 5 from 30 to 225 inclusiv [#permalink]  22 Oct 2017, 06:06
00:00

Question Stats:

71% (01:09) correct 28% (00:32) wrong based on 14 sessions
Set T consists of all multiples of 5 from 30 to 225 inclusive

 Quantity A Quantity B Mean of Set T Median of Set T

A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

Kudos for correct solution.
[Reveal] Spoiler: OA
Director
Joined: 03 Sep 2017
Posts: 521
Followers: 1

Kudos [?]: 344 [1] , given: 66

Re: Set T consists of all multiples of 5 from 30 to 225 inclusiv [#permalink]  22 Oct 2017, 09:00
1
KUDOS
The mean of set S is computed as $$\frac{\frac{40}{2}(30+225)}{40} = 127.5$$ using the formula for the sum of an arithmetic series at the numerator. The median of S, given that S has 40 elements, is the mean of the 20 and 21 elements of the series, i.e. $$\frac{125+130}{2} = 127.5$$. Then quantities A and B are equal and answer is C
Intern
Joined: 24 Feb 2018
Posts: 14
Followers: 0

Kudos [?]: 7 [1] , given: 6

Re: Set T consists of all multiples of 5 from 30 to 225 inclusiv [#permalink]  23 Mar 2019, 16:48
1
KUDOS
IlCreatore wrote:
The mean of set S is computed as $$\frac{\frac{40}{2}(30+225)}{40} = 127.5$$ using the formula for the sum of an arithmetic series at the numerator. The median of S, given that S has 40 elements, is the mean of the 20 and 21 elements of the series, i.e. $$\frac{125+130}{2} = 127.5$$. Then quantities A and B are equal and answer is C

Any set that is evenly distributed will have mean = median. In this case, the list os equally distributed as a multiple of 5. Ans - C
Re: Set T consists of all multiples of 5 from 30 to 225 inclusiv   [#permalink] 23 Mar 2019, 16:48
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# Set T consists of all multiples of 5 from 30 to 225 inclusiv

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