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Set M consists of 20 evenly spaced integers, 10 numbers of w [#permalink]
30 Aug 2018, 07:38

Expert's post

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Question Stats:

23% (00:34) correct
76% (00:43) wrong based on 21 sessions

Set M consists of 20 evenly spaced integers, 10 numbers of which are positive and 10 of which are negative.

Quantity A

Quantity B

The average (arithmetic mean) of all the numbers in set M

\(0\)

A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.

Re: Set M consists of 20 evenly spaced integers, 10 numbers of w [#permalink]
30 Aug 2018, 10:04

1

This post received KUDOS

Expert's post

sandy wrote:

Set M consists of 20 evenly spaced integers, 10 numbers of which are positive and 10 of which are negative.

Quantity A

Quantity B

The average (arithmetic mean) of all the numbers in set M

\(0\)

A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.

Nice question!

ASIDE: I've never been a fan of the term "EVENLY spaced". I worry that students believe that the difference between consecutive values must be EVEN. SO, I typically write "EQUALLY spaced."

Okay, let's solve this question by coming up with some 20-number sets that satisfy the given conditions.

CASE A: The numbers are {-19, -17, -15, -13, -11, -9, -7, -5, -3, -1, 1, 3, 5, 7, 9, 11, 13, 15, 17, 19} Here, the mean of the set is 0 So, in this case, the two quantities are EQUAL

CASE B: The numbers are {-28, -25, -22, -19, -16, -13, -10, -7, -4, -1, 2, 5, 8, 11, 14, 17, 20, 23, 26, 29} Here, the mean of the set is NOT zero So, in this case, the two quantities are NOT EQUAL

Answer: D

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Re: Set M consists of 20 evenly spaced integers, 10 numbers of w [#permalink]
14 Jan 2019, 01:38

Expert's post

GreenlightTestPrep wrote:

sandy wrote:

Set M consists of 20 evenly spaced integers, 10 numbers of which are positive and 10 of which are negative.

Quantity A

Quantity B

The average (arithmetic mean) of all the numbers in set M

\(0\)

A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.

Nice question!

ASIDE: I've never been a fan of the term "EVENLY spaced". I worry that students believe that the difference between consecutive values must be EVEN. SO, I typically write "EQUALLY spaced."

Okay, let's solve this question by coming up with some 20-number sets that satisfy the given conditions.

CASE A: The numbers are {-19, -17, -15, -13, -11, -9, -7, -5, -3, -1, 1, 3, 5, 7, 9, 11, 13, 15, 17, 19} Here, the mean of the set is 0 So, in this case, the two quantities are EQUAL

CASE B: The numbers are {-28, -25, -22, -19, -16, -13, -10, -7, -4, -1, 2, 5, 8, 11, 14, 17, 20, 23, 26, 29} Here, the mean of the set is NOT zero So, in this case, the two quantities are NOT EQUAL

Answer: D

RELATED VIDEO FROM OUR COURSE

Wow, great stuff.

greprepclubot

Re: Set M consists of 20 evenly spaced integers, 10 numbers of w
[#permalink]
14 Jan 2019, 01:38