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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # Set I consists of the integers from 11 through 100, inclusiv  Question banks Downloads My Bookmarks Reviews Important topics
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Moderator  Joined: 18 Apr 2015
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Set I consists of the integers from 11 through 100, inclusiv [#permalink]
Expert's post 00:00

Question Stats: 88% (00:50) correct 11% (01:01) wrong based on 17 sessions
Set I consists of the integers from 11 through 100, inclusive.

 Quantity A Quantity B 4 times the number of integers in set T that are multiples of 4 5times the number of integers in set T that are multiples of 5

A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________ Manager Joined: 03 Dec 2017
Posts: 65
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Kudos [?]: 16  , given: 20

Re: Set I consists of the integers from 11 through 100, inclusiv [#permalink]
1
KUDOS
how do I check how many muｌtiple of 4 between 11-100?
Can anyone give me the formula, thank you Director Joined: 20 Apr 2016
Posts: 826
WE: Engineering (Energy and Utilities)
Followers: 11

Kudos [?]: 603  , given: 124

Re: Set I consists of the integers from 11 through 100, inclusiv [#permalink]
1
KUDOS
wongpcla wrote:
how do I check how many muｌtiple of 4 between 11-100?
Can anyone give me the formula, thank you

Definitely it has a formula-

Multiple of x in the range = $$\frac{(last multiple of "x" in the range - first multiple of "x" in the range)}{x}$$ +1

Now in the first case we need the multple of 4 in the range from 11 to 100, so applying the formula

Multiple of 4 = $$\frac{(96-12)}{4}+ 1$$ (Last multiple of 4 in the range from 11 to 100 is 96 and the first multiple in the range is 12)

i.e equal to 22 nos.

In second case

Multiple of 5 = $$\frac{(100-15)}{5}+ 1$$

i.e equals to 17 nos.

Hence A > B
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Intern Joined: 13 Oct 2017
Posts: 3
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Kudos [?]: 1 , given: 0

Re: Set I consists of the integers from 11 through 100, inclusiv [#permalink]
why Last multiple of 4 in the range from 11 to 100 is not 100 but 96

pranab01 wrote:
wongpcla wrote:
how do I check how many muｌtiple of 4 between 11-100?
Can anyone give me the formula, thank you

Definitely it has a formula-

Multiple of x in the range = $$\frac{(last multiple of "x" in the range - first multiple of "x" in the range)}{x}$$ +1

Now in the first case we need the multple of 4 in the range from 11 to 100, so applying the formula

Multiple of 4 = $$\frac{(96-12)}{4}+ 1$$ (Last multiple of 4 in the range from 11 to 100 is 96 and the first multiple in the range is 12)

i.e equal to 22 nos.

In second case

Multiple of 5 = $$\frac{(100-15)}{5}+ 1$$

i.e equals to 17 nos.

Hence A > B Director Joined: 20 Apr 2016
Posts: 826
WE: Engineering (Energy and Utilities)
Followers: 11

Kudos [?]: 603  , given: 124

Re: Set I consists of the integers from 11 through 100, inclusiv [#permalink]
1
KUDOS
HsienYi wrote:
why Last multiple of 4 in the range from 11 to 100 is not 100 but 96

Yes you are right it is 100 and not 96.

So after calculation
A= 23 and B=17

Hence A>B
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Director  Joined: 07 Jan 2018
Posts: 604
Followers: 7

Kudos [?]: 544 , given: 88

Re: Set I consists of the integers from 11 through 100, inclusiv [#permalink]
HsienYi wrote:
why Last multiple of 4 in the range from 11 to 100 is not 100 but 96

pranab01 wrote:
wongpcla wrote:
how do I check how many muｌtiple of 4 between 11-100?
Can anyone give me the formula, thank you

Definitely it has a formula-

Multiple of x in the range = $$\frac{(last multiple of "x" in the range - first multiple of "x" in the range)}{x}$$ +1

Now in the first case we need the multple of 4 in the range from 11 to 100, so applying the formula

Multiple of 4 = $$\frac{(96-12)}{4}+ 1$$ (Last multiple of 4 in the range from 11 to 100 is 96 and the first multiple in the range is 12)

i.e equal to 22 nos.

In second case

Multiple of 5 = $$\frac{(100-15)}{5}+ 1$$

i.e equals to 17 nos.

Hence A > B

I guess multiples of 5 should 18 instead of 17 (100-15)/5 = 85/5 = 17 + 1 = 18
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Manager Joined: 02 Jan 2018
Posts: 66
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Kudos [?]: 30 , given: 0

Re: Set I consists of the integers from 11 through 100, inclusiv [#permalink]
T{ 12,16,......100}
100=12+(n-1)4
n=23

T{15,20,25....100}
100=15+(n-1)5
n=18

Therefore A is greater Re: Set I consists of the integers from 11 through 100, inclusiv   [#permalink] 23 Jan 2018, 09:21
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