It is currently 16 Feb 2019, 23:24

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Set A contains 120 terms with an average of 8.2. Set B conta

Author Message
TAGS:
Senior Manager
Joined: 20 May 2014
Posts: 282
Followers: 18

Kudos [?]: 50 [0], given: 220

Set A contains 120 terms with an average of 8.2. Set B conta [#permalink]  15 Oct 2017, 22:56
00:00

Question Stats:

100% (01:06) correct 0% (00:00) wrong based on 4 sessions
Set A contains 120 terms with an average of 8.2. Set B contains 240 terms with an average of 10.6. If Set A and B are combined what is the resulting average?

(A) 8.4

(B) 8.8

(C) 9.0

(D) 9.8

(E) 10.1

Kudos for correct solution.
[Reveal] Spoiler: OA
Director
Joined: 03 Sep 2017
Posts: 521
Followers: 1

Kudos [?]: 343 [1] , given: 66

Re: Set A contains 120 terms with an average of 8.2. Set B conta [#permalink]  15 Oct 2017, 23:41
1
KUDOS
We can solve it using weighted average as $$\frac{120*8.2+240*10.4}{360}=9.8$$

Manager
Joined: 01 Nov 2018
Posts: 82
Followers: 0

Kudos [?]: 36 [0], given: 20

Re: Set A contains 120 terms with an average of 8.2. Set B conta [#permalink]  23 Jan 2019, 23:45
Expert's post
If you wanna avoid a calculator ( which I recommend for easy computations like this)

lets use some basic arithmetic.

(8.2*120 + 10.6*240)/360 can be simplified since the numbers are multiples of 120, if you take that number out of the expression we have.

(8.2+ 10.6*2)/3 = (8.2+21.2)/3= 29.4/3= 9.8
Re: Set A contains 120 terms with an average of 8.2. Set B conta   [#permalink] 23 Jan 2019, 23:45
Display posts from previous: Sort by