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# Set A contains 120 terms with an average of 8.2. Set B conta

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Senior Manager
Joined: 20 May 2014
Posts: 282
Followers: 14

Kudos [?]: 48 [0], given: 220

Set A contains 120 terms with an average of 8.2. Set B conta [#permalink]  15 Oct 2017, 22:56
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Question Stats:

100% (01:07) correct 0% (00:00) wrong based on 3 sessions
Set A contains 120 terms with an average of 8.2. Set B contains 240 terms with an average of 10.6. If Set A and B are combined what is the resulting average?

(A) 8.4

(B) 8.8

(C) 9.0

(D) 9.8

(E) 10.1

Kudos for correct solution.
[Reveal] Spoiler: OA
Director
Joined: 03 Sep 2017
Posts: 521
Followers: 1

Kudos [?]: 327 [1] , given: 66

Re: Set A contains 120 terms with an average of 8.2. Set B conta [#permalink]  15 Oct 2017, 23:41
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We can solve it using weighted average as $$\frac{120*8.2+240*10.4}{360}=9.8$$

Re: Set A contains 120 terms with an average of 8.2. Set B conta   [#permalink] 15 Oct 2017, 23:41
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