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Founder  Joined: 18 Apr 2015
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Sequence S is defined as follows: S 1 = 2 [#permalink]
Expert's post 00:00

Question Stats: 90% (01:00) correct 9% (00:00) wrong based on 11 sessions
Sequence S is defined as follows:$$S_1 = 2, S_2=2^1, S_3=2^2,......, S_n=2^{n-1}$$. What is the sum of the terms is sequence S when $$n=10$$ ?

A. $$2^9$$

B. $$2^{10}$$

C. $$2^{16}$$

D. $$2^{35}$$

E. $$2^{37}$$
[Reveal] Spoiler: OA

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GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests. Intern Joined: 25 Jul 2020
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Re: Sequence S is defined as follows: S 1 = 2 [#permalink]
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The question has a bug. You mention that Sn = 2^(n - 1), but from your description the first term is 2, which is 2^1, not 2^0. And also there isn't quite any correct answer either, because

S_n = a(r^n - 1)/(r - 1). Then S_n = 2(2^n - 1) or (2^n - 1) depending on what a is, and I don't think any of the options fit it.

Edit: missed that the first term is 2, not 1, welp. Answer is $$2^10$$ then.

Last edited by Leaderboard on 27 Jul 2020, 11:03, edited 1 time in total.
Manager  Joined: 02 May 2020
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Re: Sequence S is defined as follows: S 1 = 2 [#permalink]
The question has a bug. You mention that Sn = 2^(n - 1), but from your description the first term is 2, which is 2^1, not 2^0. And also there isn't quite any correct answer either, because

S_n = a(r^n - 1)/(r - 1). Then S_n = 2(2^n - 1) or (2^n - 1) depending on what a is, and I don't think any of the options fit it.

When n=10

S = S_1 + S_2 + .... + S_9 + S_10

=> S = 2 + 2^1 + 2^2 + 2^3 + .... + 2^8 + 2^9
=> S - 2 = 2^1 + 2^2 + 2^3 + .... + 2^8 + 2^9

Lets consider RHS as X

X = 2^1 + 2^2 + 2^3 + .... + 2^8 + 2^9
2*X = 2^2 + 2^3 + .... + 2^8 + 2^9 + 2^10

subtract first equation from second

=> 2*X - X = -2^1 + 0 + 0 + 0 + .... + 0 + 0 + 2^10
=> X = 2^10 - 2

S = X + 2 = 2^10

It would have been better if it was mentioned that S_n = 2^(n-1) for n>1.
Intern Joined: 15 Mar 2020
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Re: Sequence S is defined as follows: S 1 = 2 [#permalink]
Sum = 2^9 +2^8 +... + 2^2 + 2^1 + 2
Sum = 2(2^8 + 2^7 + ... +2 + 1 + 1)
Sum = 2^2(2^7 + 2^6 + ... + 2^1 + 1 + 1) ...
Sum = 2^10 Re: Sequence S is defined as follows: S 1 = 2   [#permalink] 27 Jul 2020, 11:02
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