It is currently 09 Dec 2018, 19:50

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

s, t, and u are integers, and 10≤ s < t < u ≤ 20

Author Message
TAGS:
Moderator
Joined: 18 Apr 2015
Posts: 5122
Followers: 76

Kudos [?]: 1022 [0], given: 4624

s, t, and u are integers, and 10≤ s < t < u ≤ 20 [#permalink]  20 Dec 2017, 15:34
Expert's post
00:00

Question Stats:

71% (01:03) correct 28% (00:36) wrong based on 53 sessions
s, t, and u are integers, and 10≤ s < t < u ≤ 20

 Quantity A Quantity B $$s + \frac{t}{u}$$ 11

A. Quantity A is greater
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

kudo for the right solution and explanation
[Reveal] Spoiler: OA

_________________
Intern
Joined: 04 Jun 2016
Posts: 3
Followers: 0

Kudos [?]: 3 [1] , given: 1

Re: s, t, and u are integers, and 10≤ s < t < u ≤ 20 [#permalink]  20 Dec 2017, 20:38
1
KUDOS
we can deduce deduce the max value of A and min value of A
for Max value:
S=18
t=19
u=20
in this case A>B
for Min Value:
S=10
t=11
u=20
In that case A=10+(11/20)<11
So in this case B>A

Hence Ans D
Moderator
Joined: 18 Apr 2015
Posts: 5122
Followers: 76

Kudos [?]: 1022 [0], given: 4624

Re: s, t, and u are integers, and 10≤ s < t < u ≤ 20 [#permalink]  21 Dec 2017, 16:32
Expert's post
Added the OA. It is D.

Regards
_________________
Intern
Joined: 11 Jan 2018
Posts: 44
Followers: 0

Kudos [?]: 26 [0], given: 7

Re: s, t, and u are integers, and 10≤ s < t < u ≤ 20 [#permalink]  17 Feb 2018, 01:25
Such questions don't need any sort of calculation. What it need is just thinking. Here's how:
Minimum s can be 10. And the ratio of t to u is always less than 1. Thus the result will be between 10 and 11 i.e less than 11.
On other hand, s can be greater than 11, and thus Quantity A will become greater in that case because the ratio of t to u cannot be negative.

So, information is not sufficient to answer the question.
Choice D correct.
_________________

Persistence >>>>>>> Success

Don't say thanks, just give KUDOS.
1 kudos = 1000 Thanks

Last edited by GREMasterBlaster on 04 Mar 2018, 01:55, edited 1 time in total.
Intern
Joined: 17 Feb 2018
Posts: 10
Followers: 0

Kudos [?]: 2 [2] , given: 2

Re: s, t, and u are integers, and 10≤ s < t < u ≤ 20 [#permalink]  17 Feb 2018, 16:00
2
KUDOS
GREMasterBlaster wrote:
Such questions don't need any sort of calculation. What it need is just thinking. Here's how:
As minimum s can be 10. And the ration of t and u is always less than 1. Thus the result will be between 10 and 11 i.e less than 11.
On other hand, s can be greater than 11, and thus Quantity A will become greater in that case because the ratio of t and u cannot be negative.

So, information is not sufficient to answer the question.
Choice D correct.

I got this one wrong because I didn't look closely enough and see that it was either greater or equals, and only noticed the greater bit
Intern
Joined: 08 Apr 2018
Posts: 44
Followers: 0

Kudos [?]: 15 [0], given: 16

Re: s, t, and u are integers, and 10≤ s < t < u ≤ 20 [#permalink]  04 Jun 2018, 19:16
Carcass wrote:
s, t, and u are integers, and 10≤ s < t < u ≤ 20

 Quantity A Quantity B $$s + \frac{t}{u}$$ 11

A. Quantity A is greater
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

kudo for the right solution and explanation

For me, I calculated this by making s, t, & u equal by applying their Maximum and Minimum values of 20 and 10 respectively. Is this reasoning appropriate?
Manager
Joined: 22 Feb 2018
Posts: 118
Followers: 2

Kudos [?]: 71 [0], given: 14

Re: s, t, and u are integers, and 10≤ s < t < u ≤ 20 [#permalink]  05 Jun 2018, 17:19
We assess the biggest and lowest possible amounts for A to be able to compare it with 11.

If we want to maximize A: u should be the lowest and t and s should be the biggest possible. But there might be a tradeoff between u and (s and t).
Minimum value for u can be 12 while t is 11 and s is 10. Then A=S+T/U= 10+11/12 which is less than B, but this equation can have a bigger value, for example when s=11 and t=12 and u is whatever between 13 to 20, the value of A is bigger than 11.
(The maximum value for A is when s is maximum, because u/t is always something less than 2 and doesn’t have so much effect. And it is when s has the minimum value. For u=20, t=19 and s=18 we have the maximum value of A which is 18+19/20.)

If we want to minimize A: u should be maximum value and t&s should be minimum. But again there might be a tradeoff between u and (s and t)
Maximum value that u can have is 20 (as it can be equal to the upper bound(20) and the minimum value for s can be 10 (as it can be equal to the lower bound(10) and t can’t be equal to 10, the Lowes possible value for t can be 11. Thus we have:
A = S+T/U = 10 + 11/20 that is less than 11 (B)

Answer is D. As A is between 10+11/20 and 18+19/20

_________________

Re: s, t, and u are integers, and 10≤ s < t < u ≤ 20   [#permalink] 05 Jun 2018, 17:19
Display posts from previous: Sort by