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Expert's post 00:00

Question Stats: 92% (00:57) correct 7% (01:02) wrong based on 40 sessions
$$s=|t-2|$$

 Quantity A Quantity B $$s + 2$$ $$|t|$$

A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA Director Joined: 20 Apr 2016
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Carcass wrote:
$$s=|t-2|$$

 Quantity A Quantity B $$s + 2$$ $$|t|$$

A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

[Reveal] Spoiler: OA
OA in 24h

Since no information is given about t, so t can be integer or fraction

If consider t = integers then B > A

But if we consider t= fraction, then A > B

Hence option D
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Intern Joined: 11 Jan 2018
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Kudos [?]: 37 , given: 7

Choice D for sure.
As we have no information about t, whether it's positive or negative.
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Expert's post
Carcass wrote:
$$s=|t-2|$$

 Quantity A Quantity B $$s + 2$$ $$|t|$$

Given: s = |t - 2|

Let's plug in some values of s and t that meet the above condition that s = |t - 2|

Case 1: Notice that s = 0 and t = 2 satisfy the above equation
Let's plug these values into our Quantities A and B to get:
Quantity A: s + 2 = 0 + 2 = 2
Quantity B: |t| = |2| = 2
In this case the two Quantities are EQUAL

Case 2: Notice that s = 1 and t = 1 satisfy the given equation
Let's plug these values into our Quantities A and B to get:
Quantity A: s + 2 = 1 + 2 = 3
Quantity B: |t| = |1| = 1
In this case Quantity A IS GREATER

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Brent Hanneson – Creator of greenlighttestprep.com  Re: s=|t-2|   [#permalink] 17 Feb 2018, 11:28
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