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s=|t-2|

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s=|t-2| [#permalink] New post 06 Dec 2017, 02:32
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Question Stats:

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\(s=|t-2|\)

Quantity A
Quantity B
\(s + 2\)
\(|t|\)


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA
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Re: s=|t-2| [#permalink] New post 06 Dec 2017, 06:49
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Carcass wrote:
\(s=|t-2|\)

Quantity A
Quantity B
\(s + 2\)
\(|t|\)


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

[Reveal] Spoiler: OA
OA in 24h



Since no information is given about t, so t can be integer or fraction

If consider t = integers then B > A

But if we consider t= fraction, then A > B

Hence option D
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Re: s=|t-2| [#permalink] New post 17 Feb 2018, 01:35
Choice D for sure.
As we have no information about t, whether it's positive or negative.
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Re: s=|t-2| [#permalink] New post 17 Feb 2018, 11:28
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Expert's post
Carcass wrote:
\(s=|t-2|\)

Quantity A
Quantity B
\(s + 2\)
\(|t|\)



Given: s = |t - 2|

Let's plug in some values of s and t that meet the above condition that s = |t - 2|


Case 1: Notice that s = 0 and t = 2 satisfy the above equation
Let's plug these values into our Quantities A and B to get:
Quantity A: s + 2 = 0 + 2 = 2
Quantity B: |t| = |2| = 2
In this case the two Quantities are EQUAL

Case 2: Notice that s = 1 and t = 1 satisfy the given equation
Let's plug these values into our Quantities A and B to get:
Quantity A: s + 2 = 1 + 2 = 3
Quantity B: |t| = |1| = 1
In this case Quantity A IS GREATER

Answer: D

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Re: s=|t-2|   [#permalink] 17 Feb 2018, 11:28
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