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Running on a 10-mile loop in the same direction, Sue ran at
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sandy
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Joined: 07 Jun 2014
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GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Running on a 10-mile loop in the same direction, Sue ran at [#permalink] New post  14 Jun 2018, 14:39
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71% (01:04) correct 28% (00:52) wrong based on 49 sessions

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Running on a 10-mile loop in the same direction, Sue ran at a constant rate of 8 miles per hour and Rob ran at a constant rate of 6 miles per hour. If they began running at the same point on the loop, how many hours later did Sue complete exactly 1 more lap than Rob?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
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sandy
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Joined: 07 Jun 2014
Posts: 4804
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Re: Running on a 10-mile loop in the same direction, Sue ran at [#permalink] New post  07 Jul 2018, 04:28
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Explanation

If Sue completed exactly one more lap than Rob, she ran 10 more miles than Rob. If Rob ran d miles, then Sue ran d + 10 miles. Rob and Sue began running at the same time, so they ran for the same amount of time. Let t represent the time they spent running. Fill out a chart for Rob and Sue, using the formula Distance = Rate × Time (D = RT):

D(miles)=R(miles per hour)\(\times\)T (hours)
Robd=6\(\times\)t
Sued+10=8\(\times\)t


There are two equations:

\(d = 6t d + 10 = 8t\)

Substitute 6t for d in the second equation and then solve for t:

\(6t + 10 = 8t\)

\(10 = 2t\)

\(5 = t\)

Hence option C is correct!
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indiragre18
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Re: Running on a 10-mile loop in the same direction, Sue ran at [#permalink] New post  04 Nov 2018, 08:11
1
Difference in distance/Difference in speeds = 10/(8-6) = 5
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daina1323031
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Re: Running on a 10-mile loop in the same direction, Sue ran at [#permalink] New post  19 Dec 2020, 05:09
8t - 6t = 10
=> 2t = 5
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