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Riders board the Jelly Coaster in groups of 4 every 15 secon

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GMAT Club Legend
GMAT Club Legend
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Joined: 07 Jun 2014
Posts: 4710
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 91

Kudos [?]: 1612 [0], given: 375

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Riders board the Jelly Coaster in groups of 4 every 15 secon [#permalink] New post 18 Jun 2018, 15:03
Expert's post
00:00

Question Stats:

66% (01:18) correct 33% (01:42) wrong based on 9 sessions
Riders board the Jelly Coaster in groups of 4 every 15 seconds. If there are 200 people in front of Kurt in line, in approximately how many minutes will Kurt board the Jelly Coaster?

(A) 5
(B) 8
(C) 10
(D) 13
(E) 20
[Reveal] Spoiler: OA
1 KUDOS received
GRE Forum Moderator
Joined: 29 May 2018
Posts: 117
Followers: 0

Kudos [?]: 77 [1] , given: 3

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Re: Riders board the Jelly Coaster in groups of 4 every 15 secon [#permalink] New post 19 Jun 2018, 05:56
1
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sandy wrote:
Riders board the Jelly Coaster in groups of 4 every 15 seconds. If there are 200 people in front of Kurt in line, in approximately how many minutes will Kurt board the Jelly Coaster?

(A) 5
(B) 8
(C) 10
(D) 13
(E) 20


Sandy...let me the below is correct.

4 members for 15 seconds i.e. for 60 sec 16 members will be boarded.

Now for 200 people how many minutes does it take

16 -> 60
200 -> x

=? 60*200 / 16 = 12.5 ~ 13.

D.
GMAT Club Legend
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Joined: 07 Jun 2014
Posts: 4710
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 91

Kudos [?]: 1612 [0], given: 375

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Re: Riders board the Jelly Coaster in groups of 4 every 15 secon [#permalink] New post 19 Jun 2018, 14:35
Expert's post
Its correct!
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Sandy
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GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4710
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 91

Kudos [?]: 1612 [0], given: 375

CAT Tests
Re: Riders board the Jelly Coaster in groups of 4 every 15 secon [#permalink] New post 10 Jul 2018, 05:46
Expert's post
Explanation

To find Kurt’s wait time, determine how long it will take for 200 people to board the Jelly Coaster. The problem states that 4 people board every 15 seconds. Since there are four 15-second periods in one minute, this rate converts to 16 people per minute. To find the time, divide the “work” (the people) by this rate:

200 people ÷ 16 people per minute = 200 ÷ 16 = 12.5 minutes.

The question asks for an approximation, and the closest answer is (D). In theory there may be an additional 15 seconds while Kurt’s group is boarding (the problem doesn’t really say), but Kurt’s total wait time would still be approximately 13 minutes.
_________________

Sandy
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Re: Riders board the Jelly Coaster in groups of 4 every 15 secon   [#permalink] 10 Jul 2018, 05:46
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Riders board the Jelly Coaster in groups of 4 every 15 secon

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