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# Rectangle R has length of 30 and width 10, and square S has

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Rectangle R has length of 30 and width 10, and square S has [#permalink]  05 Jan 2017, 02:02
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Question Stats:

94% (00:29) correct 5% (00:39) wrong based on 18 sessions

Rectangle R has length of 30 and width 10, and square S has length of 5. What is the ratio of the perimeter of S to the perimeter of R ?

[Reveal] Spoiler: OA
$$\frac{1}{4}$$

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Re: Rectangle R has length of 30 and width 10, and square S has [#permalink]  09 Jan 2017, 13:54
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Explanation

The perimeter of R is $$30+ 10+ 30 + 10 = 80$$ and the perimeter of S is $$4 \times 5 = 20$$. Therefore, the perimeter of S is $$\frac{20}{80}$$ of the perimeter of R.

To enter the answer $$\frac{20}{80}$$ you should enter the numerator 20 in the top box and the denominator 80 in the bottom box.

Because the fraction does not need to be reduced to lowest terms, any fraction that is equivalent to $$\frac{20}{80}$$ is also considered correct, as long as it fits in the boxes.

For example, both of the fractions $$\frac{2}{8}$$ and $$\frac{1}{4}$$ are considered correct.

Thus, the correct answer is $$\frac{20}{80}$$ (or any equivalent fraction).
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Re: Rectangle R has length of 30 and width 10, and square S has [#permalink]  20 Jan 2019, 18:26
4+4+4+4=20
30+10+30+10 = 80

20/80=1/4
Re: Rectangle R has length of 30 and width 10, and square S has   [#permalink] 20 Jan 2019, 18:26
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