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# Rectangle R has length 30 and width 10, and square S has len

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Director
Joined: 16 May 2014
Posts: 595
GRE 1: Q165 V161
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Rectangle R has length 30 and width 10, and square S has len [#permalink]  29 May 2014, 02:21
Expert's post
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Question Stats:

100% (00:40) correct 0% (00:00) wrong based on 4 sessions
Rectangle R has length 30 and width 10, and square S has length 5. The perimeter of S is what fraction of the perimeter of R?

OA:
[Reveal] Spoiler:
$$\frac{20}{80}$$

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Director
Joined: 16 May 2014
Posts: 595
GRE 1: Q165 V161
Followers: 94

Kudos [?]: 456 [0], given: 64

Re: Practice Question # 2 [#permalink]  29 May 2014, 03:30
Expert's post

Solution

The perimeter of R is (30+10+30+10)=80.
The perimeter of S is 4*5=20.

So the answer is 20/80.

PS: Because the fraction 20/80 does not need to be reduced to lowest terms, any fraction that is equivalent to 20/80 is also considered correct, as long as it fits in the boxes. For example, both of the fractions 2/8 and 1/4 are considered correct. Thus, the correct answer is 20/80 (or equivalent).
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Intern
Joined: 18 Jun 2014
Posts: 42
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Kudos [?]: 26 [0], given: 15

Re: Rectangle R has length 30 and width 10, and square S has len [#permalink]  14 Jul 2014, 03:22
1/4
Director
Joined: 09 Nov 2018
Posts: 509
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Kudos [?]: 21 [0], given: 1

Re: Rectangle R has length 30 and width 10, and square S has len [#permalink]  20 Jan 2019, 19:28
5+5+5+5 = 20
30+10+30+10 = 80

20/80
Re: Rectangle R has length 30 and width 10, and square S has len   [#permalink] 20 Jan 2019, 19:28
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# Rectangle R has length 30 and width 10, and square S has len

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