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Rectangle R has length 30 and width 10, and square S has len

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Director
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Joined: 16 May 2014
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GRE 1: 326 Q165 V161
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Kudos [?]: 313 [0], given: 64

Rectangle R has length 30 and width 10, and square S has len [#permalink] New post 29 May 2014, 02:21
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Rectangle R has length 30 and width 10, and square S has length 5. The perimeter of S is what fraction of the perimeter of R?
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OA:
[Reveal] Spoiler:
20/80

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Director
Director
User avatar
Joined: 16 May 2014
Posts: 597
GRE 1: 326 Q165 V161
Followers: 72

Kudos [?]: 313 [0], given: 64

Re: Practice Question # 2 [#permalink] New post 29 May 2014, 03:30
Expert's post

Solution



The perimeter of R is (30+10+30+10)=80.
The perimeter of S is 4*5=20.

So the answer is 20/80.

PS: Because the fraction 20/80 does not need to be reduced to lowest terms, any fraction that is equivalent to 20/80 is also considered correct, as long as it fits in the boxes. For example, both of the fractions 2/8 and 1/4 are considered correct. Thus, the correct answer is 20/80 (or equivalent).
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Intern
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Re: Rectangle R has length 30 and width 10, and square S has len [#permalink] New post 14 Jul 2014, 03:22
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Re: Rectangle R has length 30 and width 10, and square S has len   [#permalink] 14 Jul 2014, 03:22
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Rectangle R has length 30 and width 10, and square S has len

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