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Rectangle R has length 30 and width 10, and square S has len

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Rectangle R has length 30 and width 10, and square S has len [#permalink] New post 12 Sep 2017, 13:10
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95% (00:35) correct 4% (00:27) wrong based on 101 sessions
Rectangle R has length 30 and width 10, and square S has length 5. The perimeter of S is what fraction of the perimeter of R ?

enter your value as fraction

[Reveal] Spoiler: OA
\(\frac{20}{80}\)


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Disclaimer: this question is slightly reworded in the Official Guide, located here
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Re: Rectangle R has length 30 and width 10, and square S has len [#permalink] New post 12 Sep 2017, 13:15
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Explanation

The perimeter of R is and the perimeter of S is 30 + 10 + 30 + 10 = 80, and the perimeter of S is (4)(5) = 20. Therefore, the perimeter of S is \(\frac{20}{80}\)
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Re: Rectangle R has length 30 and width 10, and square S has len [#permalink] New post 20 Jan 2019, 18:14
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10+30+10+30 = 80
5+5+5+5 = 20

80/20
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Re: Rectangle R has length 30 and width 10, and square S has len [#permalink] New post 16 Aug 2019, 01:31
Carcass wrote:
Explanation

The perimeter of R is and the perimeter of S is 30 + 10 + 30 + 10 = 80, and the perimeter of S is (4)(5) = 20. Therefore, the perimeter of S is \(\frac{20}{80}\)



shouldn't we simplify the fraction to 1/4??
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Re: Rectangle R has length 30 and width 10, and square S has len [#permalink] New post 16 Aug 2019, 01:49
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Yes, of course.

ETS clearly states that you can insert the right fraction or equivalent.

\(\frac{20}{80} = \frac{1}{4}\)
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Re: Rectangle R has length 30 and width 10, and square S has len   [#permalink] 16 Aug 2019, 01:49
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