Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Real GRE® prep. Really free. Twice monthly, join a Manhattan Prep instructor for a free one-hour GRE prep session. Next sessions are June 11 or June 28th

Magoosh is excited to offer you a free GRE practice test with video answers and explanations. If you’re thinking about taking the GRE or want to see how effective your GRE test prep has been, pinpoint your strengths and weaknesses with this quiz!

Ray is 2 inches taller than Lin, and Ray is 3 inches taller than Sam.

Quantity A

Quantity B

The average (arithmetic mean) height of Ray, Lin, and Sam

The median height of Ray, Lin, and Sam

A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.

Re: Ray is 2 inches taller than Lin, and Ray is 3 inches taller [#permalink]
08 Nov 2018, 08:39

1

This post received KUDOS

Expert's post

Carcass wrote:

Ray is 2 inches taller than Lin, and Ray is 3 inches taller than Sam.

Quantity A

Quantity B

The average (arithmetic mean) height of Ray, Lin, and Sam

The median height of Ray, Lin, and Sam

A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.

Let's write all heights in terms of Ray's height.

Let R = Ray's height (in inches) So, R - 2 = Lin's height And R - 3 = Sam's height

Average height = [R + (R-2) + (R-3)]/3 = [3R - 5]/3 = 3R/3 - 5/3 = R - 5/3

To find the median height, arrange heights in ASCENDING ORDER: R-3, R-2, R So, the median height = R-2

So, we get: QUANTITY A: R - 5/3 QUANTITY B: R - 2

Subtract R from both quantities to get: QUANTITY A: -5/3 QUANTITY B: -2

Since -5/3 is greater than -2, the correct answer is A

RELATED VIDEO FROM OUR COURSE

_________________

Brent Hanneson – Creator of greenlighttestprep.com Sign up for my free GRE Question of the Dayemails

Re: Ray is 2 inches taller than Lin, and Ray is 3 inches taller [#permalink]
09 Nov 2018, 14:30

1

This post received KUDOS

The answer is Quant A:

Ray= 2+Lin's age Ray= 3+Sam's age If Lin is aged 6 then Ray is 8 which means Sam (8-3) is 5 Quant A=5+6+8=(20/3)= 6+ Quant B=6 is the median So Quant A is greater

Please share if there is an easier way to solve this.

Re: Ray is 2 inches taller than Lin, and Ray is 3 inches taller [#permalink]
09 Nov 2018, 19:20

Expert's post

Carcass wrote:

Ray is 2 inches taller than Lin, and Ray is 3 inches taller than Sam.

Quantity A

Quantity B

The average (arithmetic mean) height of Ray, Lin, and Sam

The median height of Ray, Lin, and Sam

A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.

2 inches and 3 inches more means the lower two heights are consecutive integers.But the third height is not consecutive but slightly more.. Had the third height too been consecutive, both median and mean would be EQUAL. Because the third number is not consecutive but slightly more, the mean will be greater .

You can check with values.. x,x+1,X+3... Median is x+1 Mean is x+\(\frac{4}{3}\) So A is more.
_________________