AchyuthReddy wrote:
Quantity A |
Quantity B |
Ratio of the number of two-digit integers whose squares are three-digit numbers to the number of two-digit integers whose squares is a four-digit number |
\(\frac{1}{3}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Two-digit integers are 10 - 99
number of two-digit integers whose squares are three-digit numbers: 22 ( that is 10^2 = 100 and 31^2 = 961, the integers between this two numbers will also have 3-digit number as square)
number of two-digit integers whose squares is a four-digit number: 68 (that is 32^2 = 1024 and 99^2 = 9801, the integers between this two numbers will also have 4-digit number as square)
so,\(\frac{22}{68} = \frac{11}{34} < \frac{1}{3}\)
Option B is answer.