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Intern Joined: 15 Sep 2017
Posts: 34
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Kudos [?]: 18 , given: 2

Ratio of the number of two digit integers [#permalink] 00:00

Question Stats: 52% (01:19) correct 47% (02:01) wrong based on 23 sessions
 Quantity A Quantity B Ratio of the number of two-digit integers whose squares are three-digit numbers to the number of two-digit integers whose squares is a four-digit number $$\frac{1}{3}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

Last edited by Carcass on 11 Sep 2018, 10:04, edited 1 time in total.
Edited by Carcass
Founder  Joined: 18 Apr 2015
Posts: 13927
GRE 1: Q160 V160 Followers: 315

Kudos [?]: 3687 , given: 12946

Re: Ratio of the number of two digit integers [#permalink]
Expert's post
Founder  Joined: 18 Apr 2015
Posts: 13927
GRE 1: Q160 V160 Followers: 315

Kudos [?]: 3687 , given: 12946

Re: Ratio of the number of two digit integers [#permalink]
Expert's post
Intern Joined: 29 Jun 2018
Posts: 10
Followers: 0

Kudos [?]: 11 , given: 0

Re: Ratio of the number of two digit integers [#permalink]

The numbers 10........31 have squares of 3digit .These are 22 numbers.

32......99 have squares of 4 digit.These are 68 numbers.

So we are comparing, 22/68 and 1/3

So the answer is B.  Intern Joined: 15 Sep 2017
Posts: 34
Followers: 0

Kudos [?]: 18  , given: 2

Re: Ratio of the number of two digit integers [#permalink]
1
KUDOS
AchyuthReddy wrote:
 Quantity A Quantity B Ratio of the number of two-digit integers whose squares are three-digit numbers to the number of two-digit integers whose squares is a four-digit number $$\frac{1}{3}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Two-digit integers are 10 - 99
number of two-digit integers whose squares are three-digit numbers: 22 ( that is 10^2 = 100 and 31^2 = 961, the integers between this two numbers will also have 3-digit number as square)

number of two-digit integers whose squares is a four-digit number: 68 (that is 32^2 = 1024 and 99^2 = 9801, the integers between this two numbers will also have 4-digit number as square)
so,$$\frac{22}{68} = \frac{11}{34} < \frac{1}{3}$$ Re: Ratio of the number of two digit integers   [#permalink] 12 Sep 2018, 02:49
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