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Rates 1 problem-two machines work at a constant rate

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Rates 1 problem-two machines work at a constant rate [#permalink] New post 15 Sep 2015, 03:33
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two machines work at a constant rate to produce bottles . machine A produces in 2/5 of an hour . machine B produces y bottles in 3/5 of an hour . which of the following combinations of machines can produce atleast 5y bottles in 2 hours.
Indicate all such statements
1. Machine A alone.
II. Machine B alone.
III. Both machines A and B

How to solve this problem. ?
[Reveal] Spoiler: OA
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Joined: 07 Jun 2014
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GRE 1: Q167 V156
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Re: Rates 1 problem [#permalink] New post 17 Sep 2015, 06:25
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Ayesha6194 wrote:
two machines work at a constant rate to produce bottles . machine A produces in 2/5 of an hour . machine B produces y bottles in 3/5 of an hour . which of the following combinations of machines can produce atleast 5y bottles in 2 hours.
Indicate all such statements
1. Machine A alone.
II. Machine B alone.
III. Both machines A and B

How to solve this problem. ?


You don't really need to solve this question because there are only three feasible combinations mentioned.

Machine A produces a bottle in \(\frac{2}{5}\) hours. So in 2 hours it will 2 / \(\frac{2}{5}\) = 5. I chose machine A first because it is faster of the two machines.

Hence to make more than 5 bottles you need more than Machine A so III is the only possible option.

The key words to focus on in this problem is "more than 5 bottles"
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Re: Rates 1 problem [#permalink] New post 01 Mar 2018, 01:05
sandy wrote:
Ayesha6194 wrote:
two machines work at a constant rate to produce bottles . machine A produces in 2/5 of an hour . machine B produces y bottles in 3/5 of an hour . which of the following combinations of machines can produce atleast 5y bottles in 2 hours.
Indicate all such statements
1. Machine A alone.
II. Machine B alone.
III. Both machines A and B

How to solve this problem. ?


You don't really need to solve this question because there are only three feasible combinations mentioned.

Machine A produces a bottle in \(\frac{2}{5}\) hours. So in 2 hours it will 2 / \(\frac{2}{5}\) = 5. I chose machine A first because it is faster of the two machines.

Hence to make more than 5 bottles you need more than Machine A so III is the only possible option.

The key words to focus on in this problem is "more than 5 bottles"


The stem says "atleast 5y bottles in 2 hours" answer is A and C
Re: Rates 1 problem   [#permalink] 01 Mar 2018, 01:05
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Rates 1 problem-two machines work at a constant rate

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