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r > s > zero

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r > s > zero [#permalink] New post 18 Mar 2018, 10:14
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Question Stats:

68% (00:24) correct 31% (00:32) wrong based on 60 sessions
r > s > 0
Quantity A
Quantity B
\(\frac{rs}{r}\)
\(\frac{rs}{s}\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: r > s > zero [#permalink] New post 26 Mar 2018, 04:32
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Quantity B is greater. Here's how:

We can cancel out the two r in Quantity A. Also we can cancel out the two s in Quantity B.
After simplifying both quantities we'll get,

Quantity A: s
Quantity B: r

As it is given that r is greater than s

Thus, Quantity B is greater.
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Re: r > s > zero [#permalink] New post 02 May 2018, 07:05
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Expert's post
Carcass wrote:
r > s > 0
Quantity A
Quantity B
\(\frac{rs}{r}\)
\(\frac{rs}{s}\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Given:
Quantity A: rs/r
Quantity B: rs/s

Since r and s DO NOT equal 0, we can safely simplify the two quantities to get:
Quantity A: s
Quantity B: r

Since we're told that r > s > 0, we can conclude that r is greater.

Answer: B

Cheers,
Brent
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Re: r > s > zero [#permalink] New post 11 May 2018, 18:43
NUmerator si same in all the cases. Only thing at changes is the denominator. In any condition, denominator in A is greater hence the overall fraction in A is smaller
Re: r > s > zero   [#permalink] 11 May 2018, 18:43
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