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# r > s > zero

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Moderator
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r > s > zero [#permalink]  18 Mar 2018, 10:14
Expert's post
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Question Stats:

67% (00:25) correct 32% (00:32) wrong based on 58 sessions
r > s > 0
 Quantity A Quantity B $$\frac{rs}{r}$$ $$\frac{rs}{s}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Intern
Joined: 11 Jan 2018
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Kudos [?]: 32 [1] , given: 7

Re: r > s > zero [#permalink]  26 Mar 2018, 04:32
1
KUDOS
Quantity B is greater. Here's how:

We can cancel out the two r in Quantity A. Also we can cancel out the two s in Quantity B.
After simplifying both quantities we'll get,

Quantity A: s
Quantity B: r

As it is given that r is greater than s

Thus, Quantity B is greater.
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Re: r > s > zero [#permalink]  02 May 2018, 07:05
1
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Expert's post
Carcass wrote:
r > s > 0
 Quantity A Quantity B $$\frac{rs}{r}$$ $$\frac{rs}{s}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Given:
Quantity A: rs/r
Quantity B: rs/s

Since r and s DO NOT equal 0, we can safely simplify the two quantities to get:
Quantity A: s
Quantity B: r

Since we're told that r > s > 0, we can conclude that r is greater.

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com

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Manager
Joined: 26 Jan 2018
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Re: r > s > zero [#permalink]  11 May 2018, 18:43
NUmerator si same in all the cases. Only thing at changes is the denominator. In any condition, denominator in A is greater hence the overall fraction in A is smaller
Re: r > s > zero   [#permalink] 11 May 2018, 18:43
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# r > s > zero

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