@Carcass
Sorry about the pictures.
@trunks14
Here's a simple way to imagine it: for any right triangle, the two legs squared will equal the hypotenuse squared. But what if you kept the two legs the same length and squeezed down the hypotenuse to something smaller? Then we know that the two legs squared will now be larger than the new hypotenuse squared, and we also know that the angle must now be less than 90°.
Similarly, if we widen the two legs, the hypotenuse would now have to be larger, but the angle now exceeds 90°.
This is actually a general rule:
a^2 + b^2 < c^2 when the angle is less than 90°
and
a^2 + b^2 > c^2 when the angle is greater than 90°
So from these thought experiments we know that in the original question the two sides of the triangle
squared on either side of the 88° angle must be larger than the two sides of the triangle
squared on either side of the 92° angle. So again the answer is B.
A picture would've been much easier and less wordy but that's not allowed, haha.
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