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QOTD#20 One cup of nuts that contains exactly half peanuts a

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GMAT Club Legend
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Joined: 07 Jun 2014
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GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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QOTD#20 One cup of nuts that contains exactly half peanuts a [#permalink] New post 03 Apr 2017, 03:06
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One cup of nuts that contains exactly half peanuts and half cashews is added to a bowl of nuts that is exactly one third peanuts, one third cashews, and one third almonds. This results in a three-cup mixture of nuts. What fraction of the new nut mixture is peanuts?

Drill 3
Question: 3
Page: 318


[Reveal] Spoiler: OA
\(\frac{7}{18}\)

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GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4749
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 93

Kudos [?]: 1650 [0], given: 396

CAT Tests
Re: QOTD#20 One cup of nuts that contains exactly half peanuts a [#permalink] New post 03 Apr 2017, 05:28
Expert's post
Explanation

The total mixture contains three cups, so the second bowl must contain two cups.

This 2-cup bowl of nuts divided into even thirds consists of \(\frac{2}{3}\)cups peanuts, cups cashews, \(\frac{2}{3}\) and \(\frac{2}{3}\) cups almonds.

Combining this with the 1-cup mixture of \(\frac{1}{2}\) cup peanuts and \(\frac{1}{2}\) cup cashews results in \(\frac{7}{6}\) cups peanuts in a 3-cup mixture.

So, \(\frac{6}{3}=\frac{7}{18}\) of the new nut mixture is peanuts.

Hence \(\frac{7}{18}\) is correct.
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Sandy
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Re: QOTD#20 One cup of nuts that contains exactly half peanuts a   [#permalink] 03 Apr 2017, 05:28
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QOTD#20 One cup of nuts that contains exactly half peanuts a

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