Explanation

Let x be the maximum height, in centimeters, to which the tank can be filled with water, so that when the water freezes, the ice will not rise above the top of the tank. Based on the assumption that the volume of water increases by 10 percent when it freezes and the fact that the length and width of the tank will not change, the maximum height of the ice is 1.1x centimeters. Since the height of the tank is 270 centimeters, it follows that 1.1x = 270, or, to the nearest whole number, x = 245. The correct answer is Choice D.
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The solution makes sense, but I'm wondering, why doesn't the following solution work?

The height of the tank is 270, and 10% of 270 is 27. Therefore, if we fill up water to the height of 270-27=243, we will have 10% of the height left when the water freezes.

You can test ypur soultion.

We know volume increases by 10% when frozen so if the water level was 243 then frozen water level would be 243 + 10% of 243 = 267.3. This is less than 270.

The reason for this is you need to look at the base for percentage. For example

10% of 100 is 10. So if we add we get 110.
But 10% of 110 is 11. So if we substract we get 99. Not 100.
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I took a slight detour with this exercise:

calculated the volume off the bat-->2673000

then I imagined that we keep the same values other than the hight


110*90*x*1.1=2673000

X standing there for the sake of seeing what the maximum value could have in the case of freezing

x yielding a result back of--->245,45

Thereby answer D

How did you arrive to the step
110*90*x*1.1= volume?
if we use the percentage increase formula
the you should get
110*90*x= volume*1.1

As much as I would like to help you, I am momentarily slammed with all sorts of different academia readings. I'll try to explain what I did next week, presuming that I will be able to distinguish what I even did here.

Alright no problem , could you tell me which books you're using

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[quote="SaiTarun994"]Alright no problem , could you tell me which books you're using

Posted from my mobile device

Gregmat, I think in a similar way as he does.

Can someone pls explain this ans?

Hi shritisingh

Here is a complete explanation. Though it would be great if you can add where you faltered in the calculation so that I can help you more.

Regards,
R