Carcass wrote:

If x and y are integers \(x = \frac{(2)(3)(4)(5)(7)(11)(13)}{39y}\) and which of the following could be the value of y ?

A) 15

B) 28

C) 38

D) 64

E) 143

Practice Questions

Question: 16

Page: 180

GIVEN: \(x = \frac{(2)(3)(4)(5)(7)(11)(13)}{39y}\)

Prime factorize the denominator to get: \(x = \frac{(2)(3)(4)(5)(7)(11)(13)}{(3)(13)y}\)

Simplify: \(x = \frac{(2)(4)(5)(7)(11)}{y}\)

In order for x to be an integer, y must be a divisor of \((2)(4)(5)(7)(11)\)

Scan the answer choices....

28 is a divisor of (2)(

4)(5)(

7)(11)

Answer: B

Cheers,

Brent

_________________

Brent Hanneson – Creator of greenlighttestprep.com

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