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Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. QOTD # 16 If x and y are integers and which of the followin  Question banks Downloads My Bookmarks Reviews Important topics
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Founder  Joined: 18 Apr 2015
Posts: 7021
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Kudos [?]: 1371 , given: 6384

QOTD # 16 If x and y are integers and which of the followin [#permalink]
Expert's post 00:00

Question Stats: 75% (01:23) correct 25% (01:36) wrong based on 16 sessions
If x and y are integers $$x = \frac{(2)(3)(4)(5)(7)(11)(13)}{39y}$$ and which of the following could be the value of y ?

A) 15
B) 28
C) 38
D) 64
E) 143

Practice Questions
Question: 16
Page: 180
[Reveal] Spoiler: OA

_________________
Founder  Joined: 18 Apr 2015
Posts: 7021
Followers: 117

Kudos [?]: 1371 , given: 6384

Re: QOTD # 16 If x and y are integers and which of the followin [#permalink]
Expert's post
Explanation

The OE is a bit cumbersome and the question might be attacked in a clever way. Boil down the fraction, we ca eliminate 39 at the denominator because 3*13=39 so indeed we will end up with $$\frac{x=2*4*5*7*11}{y}$$.

Now. the stem says that X is an integer and to obtain an integer we should find a number for Y that has the same prime factors of the numerator

$$x= \frac{2^3 * 5*7*11}{y}$$

Looking at the answer choice the only number that satisfies our condition is $$28 = 2^2*7$$. The other answer choices lack prime numbers that satisfy our condition.

For instance, 15=3*5 but 3 is not in our numerator.

The correct option is B
_________________
GRE Instructor Joined: 10 Apr 2015
Posts: 2027
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Kudos [?]: 1842 , given: 9

Re: QOTD # 16 If x and y are integers and which of the followin [#permalink]
Expert's post
Carcass wrote:
If x and y are integers $$x = \frac{(2)(3)(4)(5)(7)(11)(13)}{39y}$$ and which of the following could be the value of y ?

A) 15
B) 28
C) 38
D) 64
E) 143

Practice Questions
Question: 16
Page: 180

GIVEN: $$x = \frac{(2)(3)(4)(5)(7)(11)(13)}{39y}$$

Prime factorize the denominator to get: $$x = \frac{(2)(3)(4)(5)(7)(11)(13)}{(3)(13)y}$$

Simplify: $$x = \frac{(2)(4)(5)(7)(11)}{y}$$

In order for x to be an integer, y must be a divisor of $$(2)(4)(5)(7)(11)$$

28 is a divisor of (2)(4)(5)(7)(11)

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com  Re: QOTD # 16 If x and y are integers and which of the followin   [#permalink] 12 Jun 2019, 07:44
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