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# QOTD # 1 X^5 and X^4

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Founder
Joined: 18 Apr 2015
Posts: 7405
Followers: 125

Kudos [?]: 1451 [0], given: 6615

QOTD # 1 X^5 and X^4 [#permalink]  07 Sep 2016, 02:24
Expert's post
00:00

Question Stats:

100% (00:07) correct 0% (00:00) wrong based on 23 sessions
$$x < 0$$

 Quantity A Quantity B $$x^5$$ $$x^4$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Practice Questions
Question: 1
Page: 177
[Reveal] Spoiler: OA

_________________
Founder
Joined: 18 Apr 2015
Posts: 7405
Followers: 125

Kudos [?]: 1451 [1] , given: 6615

Re: QOTD # 1 X^5 and X^4 [#permalink]  07 Sep 2016, 02:26
1
KUDOS
Expert's post
Explanation

If x < 0, then $$x^5$$ < 0 and $$x^4$$ > 0. Thus $$x^5$$ < $$x^4$$ , and the correct answer is Choice B.
_________________
GRE Instructor
Joined: 10 Apr 2015
Posts: 2175
Followers: 65

Kudos [?]: 1989 [1] , given: 20

Re: QOTD # 1 X^5 and X^4 [#permalink]  07 Sep 2016, 06:17
1
KUDOS
Expert's post
Carcass wrote:

x < 0
 Quantity A Quantity B $$X^5$$ $$X^4$$

Another approach:
Quantity A: x⁵
Quantity B: x⁴

Since we're told that x < 0, we can be certain that x ≠ 0.
From this, we can conclude that x⁴ is POSITIVE, which means we can divide both quantities by x⁴ to get:
Quantity A: x
Quantity B: 1

Since we're told that x < 0 (i.e., x is NEGATIVE), we can be certain that 1 is greater than x

[Reveal] Spoiler:
B

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Re: QOTD # 1 X^5 and X^4   [#permalink] 07 Sep 2016, 06:17
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