Quantity A: (-5)(-3)(-1)(1)(3)(5)(7)(9)(11)(13)
Quantity B: (-12)(-10)(-8)(-6)(-4)(-2)(0)(2)(4)(6)

In Quantity A, we have 3 negative integers. So, the product of these 3 values will be NEGATIVE
Also in Quantity A, the 7 positive integers will have a product that is POSITIVE
So, Quantity A = (NEGATIVE)(POSITIVE) = NEGATIVE

In Quantity B, one of the values is ZERO, which means the product = 0

We now have:
Quantity A: NEGATIVE
Quantity B: 0

Answer: B

Cheers,
Brent
_________________

A smart approach is advisable here. The question is specifically made time-consuming.

A) -5 -3 -1 1 3 5 7 9 11 13

B) -12 -10 -8 -6 -4 -2 2 4 6

-----------------------------------------------

Cancel out the opposite

A) 7 9 11 13

B) -12 -10 -8

A is the must answer. Without any calculation.

To produce a particular radio model, it costs a manufacturer $30 per
radio, and it is assumed that if 500 radios are produced, all of them will be sold. What
must be the selling price per radio to ensure that the profit (revenue from the sales minus
the total production cost) on the 500 radios is greater than $8,200 ?

correct: B
The product of odd integers from -5 to 13 inclusive: -5 * -3 * -1 * 1 * 3 * 5 * 7 * 9 * 11 * 13
The product of even integers from -12 to 6 inclusive: -12 * -10 * -8 * -6 * -4 * -2 * 0 * 2 * 4 * 6
The first thing to check is if any of the products are negative. Else in case of having same sign (both negative or both positive, we will compare their values.)
A consists of 3 negative numbers, as 3 is odd, the result is negative.
B consists of 6 negative numbers, as 6 is even, the result must be positive, but there is a 0 in the product elements, so B equals to 0.
as A is negative and B is 0, B is bigger than A.
_________________

Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.