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# Practice Question #5- 60 jelly beans — 22 white, 18 green

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Practice Question #5- 60 jelly beans — 22 white, 18 green [#permalink]  29 May 2014, 02:08
Expert's post
00:00

Question Stats:

50% (00:48) correct 50% (02:45) wrong based on 4 sessions
A certain jar contains 60 jelly beans — 22 white, 18 green, 11 yellow, 5 red and 4 purple. If a jelly bean is to be chosen at random, what is the probability that the jelly bean will be neither red nor purple?

(A) 0.09
(B) 0.15
(C) 0.54
(D) 0.85
(E) 0.91
[Reveal] Spoiler: OA

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Re: Practice Question #5- 60 jelly beans — 22 white, 18 green [#permalink]  29 Nov 2017, 11:19
Expert's post
Explanation

Since there are 5 red and 4 purple jelly beans in the jar, there are 51 that are neither red nor purple and the probability of selecting one of these is $$\frac{51}{60}$$. Since all of the answer choices are decimals, you must convert the fraction to its decimal equivalent, 0.85. Thus the correct answer is Choice D, 0.85.
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Re: Practice Question #5- 60 jelly beans — 22 white, 18 green   [#permalink] 29 Nov 2017, 11:19
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