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Practice Question #1- Solve 5x + 32 = 4 - 2x

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Director
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Joined: 16 May 2014
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GRE 1: Q165 V161
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Practice Question #1- Solve 5x + 32 = 4 - 2x [#permalink] New post 29 May 2014, 01:52
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Question Stats:

100% (00:01) correct 0% (00:00) wrong based on 1 sessions
If \(5x + 32 = 4 - 2x\), what is the value of x?

(A) -4
(B) -3
(C) 4
(D) 7
(E) 12
[Reveal] Spoiler: OA

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Re: Practice Question #1- Solve 5x + 32 = 4 - 2x [#permalink] New post 05 Apr 2016, 14:46
-4
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Re: Practice Question #1- Solve 5x + 32 = 4 - 2x [#permalink] New post 07 Jun 2017, 07:12
rampragash wrote:
-4


How did you get -4. Please show you work.
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Re: Practice Question #1- Solve 5x + 32 = 4 - 2x [#permalink] New post 27 Sep 2017, 07:41
leonidbasin1 wrote:
rampragash wrote:
-4


How did you get -4. Please show you work.


Easy algebra.

If we start from \(5x + 32 = 4 - 2x\), we can sum 2x on both sides and subtract 32 on both sides to get \(7x = -28\). Then, dividing both sides by 7 we get \(x = -4\). Answer A!
Re: Practice Question #1- Solve 5x + 32 = 4 - 2x   [#permalink] 27 Sep 2017, 07:41
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Practice Question #1- Solve 5x + 32 = 4 - 2x

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