when you analyze a quadratic eqn.

see the base of \(x^2\) part of the eqn in the form \(ax^2\) + \(bx\) + \(c\)

For Point

P \(x^2\) has a

+ve base while for Point

Q \(x^2\) has a

-ve base

Therefore we can conclude that point is curved up i.e U shaped while Point Q is curved down i.e reverse of U shaped

This is all that is required to ans this question.

Since the U shaped part has a minimum y coordinate less than the maximum y coordinate of reverse U shaped graph.

option B should be the ans

Please share the official ans

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This is my response to the question and may be incorrect. Feel free to rectify any mistakes