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Point P lies on y=X^2−1 and Point Q lies on y=−X^2

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Intern
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Joined: 06 Oct 2018
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Point P lies on y=X^2−1 and Point Q lies on y=−X^2 [#permalink] New post 03 Dec 2018, 23:13
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Question Stats:

66% (00:00) correct 33% (01:01) wrong based on 3 sessions
Point P lies on \(y=X^2−1\) and Point Q lies on \(y=−X^2+1\)

Quantity A
Quantity B
minimum y coordinate value of Point P
maximum y coordinate value of Point Q


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given


[Reveal] Spoiler:
Ans - B

Last edited by Arun1992 on 05 Dec 2018, 09:29, edited 1 time in total.
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Re: Point P lies on y=X^2−1 and Point Q lies on y=−X^2 [#permalink] New post 05 Dec 2018, 08:34
when you analyze a quadratic eqn.
see the base of \(x^2\) part of the eqn in the form \(ax^2\) + \(bx\) + \(c\)

For Point P \(x^2\) has a +ve base while for Point Q \(x^2\) has a -ve base
Therefore we can conclude that point is curved up i.e U shaped while Point Q is curved down i.e reverse of U shaped
This is all that is required to ans this question.

Since the U shaped part has a minimum y coordinate less than the maximum y coordinate of reverse U shaped graph.
option B should be the ans

Please share the official ans
_________________

This is my response to the question and may be incorrect. Feel free to rectify any mistakes

Re: Point P lies on y=X^2−1 and Point Q lies on y=−X^2   [#permalink] 05 Dec 2018, 08:34
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Point P lies on y=X^2−1 and Point Q lies on y=−X^2

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