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Re: Percentage of a Number compared with Fraction of a Number [#permalink]
09 Oct 2016, 06:37

Since no information has been given about x so it could be integer,decimal,rational,irrational number or even 0.So we have three cases to test values of Quantity A & B

Case 1: if x>0 => let x = 2

Quantity A

Quantity B

0.3*2=0.6

0.3077*2~0.6164

=> Quantity A < Quantity B

Case 2: if x=0 => let x = 2

Quantity A

Quantity B

0.3*0=0.6

0.3077*0=0

=> Quantity A = Quantity B

Case 3: if x<0 => let x = -2

Quantity A

Quantity B

-0.3*2=-0.6

-0.3077*2~-0.6164

=> Quantity A > Quantity B

Therefore answer is D and answer cannot be determined from given information

Re: Percentage of a Number compared with Fraction of a Number [#permalink]
12 Nov 2016, 08:03

2

This post received KUDOS

Expert's post

yasir9909 wrote:

Quantity A

Quantity B

30 percent of x

(4/13) of x

Whenever I have the option of plugging in values, I first look for equality That is, I look for a value that will make the two quantities equal. Right away, I see that if x = 0, then Quantities A and B are equal. So, EITHER the two quantities are always equal (which means the answer is A) OR the two quantities are not always equal (which means the answer is D) So, in a matter of seconds, I know the correct answer is A or D

Now plug in a different value for x. How about x = 1 We get... Quantity A: 30 percent of 1 = 3/10 of 1 = 3/10 Quantity B: (4/13) of 1 = 4/13 These two values are clearly NOT equal.

So, the answer must be D

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