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# Patrick purchased 80 pencils and sold them at a loss equal

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Joined: 18 Apr 2015
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Patrick purchased 80 pencils and sold them at a loss equal [#permalink]  30 Apr 2019, 01:02
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Question Stats:

36% (01:16) correct 64% (01:02) wrong based on 25 sessions
Patrick purchased 80 pencils and sold them at a loss equal to the selling price of 20 pencils.

 Quantity A Quantity B Cost of 80 pencils Selling price of 100 pencils

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Intern
Joined: 21 Mar 2019
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Kudos [?]: 2 [1] , given: 2

Re: Patrick purchased 80 pencils and sold them at a loss equal [#permalink]  30 Apr 2019, 06:38
1
KUDOS
let CP of 1 pencil = 1, so CP of 80 pencils = 80

then,

CP - SP = LOSS (when it costs more than you sell it for)

Assume SP of 80 pencils to be SP, so for SP of 20 pencils it (20/80 * SP)
it is mentioned LOSS is SP of 20 pencils

substituting,
80 - SP = (20/80 * SP)
80 - SP = 1/4 * SP
80 = 5/4 * SP

SP = 64

Now this value is SP of 80 pencils, so SP of 100 pencils = (100 * 64 / 80) = 80
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Re: Patrick purchased 80 pencils and sold them at a loss equal [#permalink]  09 Jul 2019, 23:23
1
KUDOS
Number of pencils with Patrick : 80
Let us assume that cost price of 1 pencil = 1
So, the cost price of 80 pencils will be 80.
Lets assume total selling price 1 pencil = SP
Loss = Cost price – Selling price
80 – 80SP = 20SP
80 = 100SP
SP = 8/10= 4/5
QTY A : Cost price of 80 pencils = 80
QTY B: Selling price of 100 pencils = 4/5*100=80
Re: Patrick purchased 80 pencils and sold them at a loss equal   [#permalink] 09 Jul 2019, 23:23
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