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Parallelogram OPQR lies in the xy-plane
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27 Dec 2015, 19:42
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86% (03:23) correct
13% (02:07) wrong based on 165 sessions
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#GREpracticequestion Parallelogram OPQR lies in the xy-plane.jpg [ 15.64 KiB | Viewed 8389 times ]
Parallelogram OPQR lies in the xy-plane, as shown in the figure above. The coordinates of point P are (2, 4) and the coordinates of point Q are (8, 6). What are the coordinates of point R ?
A. (3, 2) B. (3, 3) C. (4, 4) D. (5, 2) E. (6, 2)
Practice Questions Question: 10 Page: 158 Difficulty: hard
Re: Parallelogram OPQR lies in the xy-plane
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20 Mar 2018, 13:27
7
Expert Reply
sandy wrote:
Parallelogram OPQR lies in the xy-plane, as shown in the figure above. The coordinates of point P are (2, 4) and the coordinates of point Q are (8, 6). What are the coordinates of point R ?
A. (3, 2) B. (3, 3) C. (4, 4) D. (5, 2) E. (6, 2)
KEY CONCEPT: Since OPQR is a parallelogram, we know that sides PQ and OR are parallel AND the same length
Let's take a closer look at side PQ
Notice that, to get from point P to point Q we must move 2 units UP and move 6 units RIGHT.
Since sides PQ and OR are parallel AND the same length, the same must apply to points O and R So, if we start from point O (at 0,0) and move 2 units UP and move 6 units RIGHT, we must get to point R
From here, it we can determine the coordinates of point R
Answer: E
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Re: Parallelogram OPQR lies in the xy-plane
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27 Apr 2016, 08:27
1
It is a parallelogram. If the distance between O to P in “X”axis is 2, the distance between R to Q in “X” axis must be 2. So, Distance between O to R in “X” axis will be 8-2= 6. Similarly, If the distance between O to P in “Y”axis is 4, the distance between Q to R in “Y” axis must be 4. So, Distance between O to R in “Y” axis will be 6-4= 2. The point at R= (6,2)
Re: Parallelogram OPQR lies in the xy-plane
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15 Sep 2017, 00:14
1
I have used the fact that PQ and OR must be parallel since the figure is a parallelogram, then the slope of PQ must be the same as OR. The slope of PQ is equal to 1/3, thus, given that O=(0,0), R must be equal to (6,2) in order to have a slope of 1/3, i.e. (2-0)/(6-0) = 1/3.
Re: Parallelogram OPQR lies in the xy-plane
[#permalink]
27 Jun 2018, 20:47
The slope of the line from the origin to point P is the same as the slope of the line from point Q to R because we have a parallelgram. The same is true for the lines between points P and Q and the origin and point R. The slope of the line from the origin to P is 2, so it follows that the slope of the line between between Q and R is also 2. Now we can determine the equations of the lines between the origin and R and also between Q and R. Given points P and Q, it is easy to see that the slope line between these points is 1/3. It follows that the slope of the line between the origin and R is also 1/3. Hence, the equation of the line from the origin to R is y=1/3X. Using the fact that the slope of the line between Q and R is 2 and we are given that the coordinates of Q are (8,6), we can determine the equation of the line between Q and R to be Y=2X-10 using the point-slope method. We can determine the coordinates of R by setting the equations of the lines Y=1/3X and Y=2X-10 together. Solve for X: 1/3X=2X-10, So X is 6. Plug 6 into Y=1/3X or Y=2X-10 to get Y=2. Answer: (6,2).
Parallelogram OPQR lies in the xy-plane
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31 Mar 2021, 06:49
sandy wrote:
Attachment:
#GREpracticequestion Parallelogram OPQR lies in the xy-plane.jpg
Parallelogram OPQR lies in the xy-plane, as shown in the figure above. The coordinates of point P are (2, 4) and the coordinates of point Q are (8, 6). What are the coordinates of point R ?
A. (3, 2) B. (3, 3) C. (4, 4) D. (5, 2) E. (6, 2)
In Parallelogram, Opposite sides are parallel and equal