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P is the intersection of the two diagonals of rectangle ABeD

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Founder
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P is the intersection of the two diagonals of rectangle ABeD [#permalink]  08 Oct 2019, 15:18
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76% (00:31) correct 23% (00:37) wrong based on 13 sessions
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#greprepclub P is the intersection of the two diagonals.jpg [ 7.47 KiB | Viewed 380 times ]

P is the intersection of the two diagonals of rectangle $$ABCD$$.

 Quantity A Quantity B The shortest distance from P to side AB The length of side AB

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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[Reveal] Spoiler: OA

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Intern
Joined: 09 Oct 2019
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Kudos [?]: 5 [1] , given: 0

Re: P is the intersection of the two diagonals of rectangle ABeD [#permalink]  09 Oct 2019, 09:43
1
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The shortest distance is straight line from p to AB which will be half of side BC
QA:4
QB:5
so B>A
GRE Forum Moderator
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Kudos [?]: 80 [0], given: 2

Re: P is the intersection of the two diagonals of rectangle ABeD [#permalink]  24 Dec 2019, 05:14
Given: P is the intersection of the two diagonals of rectangle ABCD.

So if we go by symmetry then P is the midpoint of the ABCD

The shortest distance from P to side AB = BC/2 = 4

Re: P is the intersection of the two diagonals of rectangle ABeD   [#permalink] 24 Dec 2019, 05:14
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