Prime numbers are 2,3,5,7...etc

Given \(p^2\) is odd , so it has be from 3,5,7.... other than 2.

We are told that \(p + w < 6\)

Least value of p can be 3 and w has to be 2 or else result will be greater than 6.

So w has to be 2.

col b > a.

B.

Since the question doesn't specify if the numbers are negative, why is the answer not D - cannot be solved? For example: If p = -5, then it is still a single digit prime, could still result in an odd square, and could satisfy the inequality of -5 + w <6. In this example, w could equal 3 and then the solution would be equal. Since there are multiple solutions, shouldn't the answer to this question be D?

p and w are single-digit prime numbers

\(p+w<6\)

the only prime numbers, which are integers and must be positive, that the sum is < 6 are 2 and 3.

However, \(p^2\) is odd so p must 3. and w must be 2

QA is w which is = 2

QB is 3

B > A

B is the answer



Prime numbers CANNOT be negative.

More on this in our quant book https://greprepclub.com/forum/gre-math- ... -2609.html
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They have given that p and w are single digit prime numbers:
So the possibilities are 2,3,5,7.
The sum of the two should be less than 6. That rules out 5,7.
So the two numbers are 2,3. Now the square of p is odd so p is 3.
So w is 2. So B is greater.