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Re: Oranges are bought at the rate of 10 for [#permalink]
05 Dec 2018, 08:54

Expert's post

nadeem790 wrote:

Oranges are bought at the rate of 10 for $25 and sold at the rate of 9 for $25. The profit is:

a) \(9 \frac{1}{11}\) %

b) \(10\)%

c) \(11 \frac{1}{9}\) %

d) \(12 \frac{1}{2}\) % e) \(2 \frac{1}{2}\) %

Cost price = the rate of 10 for $25= \(\frac{25}{10}\) and Selling price = sold at the rate of 9 for $25= \(\frac{25}{9}\) Profit = \((\frac{25}{9}-\frac{25}{10})/\frac{25}{10}=\frac{25}{90}/\frac{25}{10}=\frac{1}{9}\) Profit % = \(100*\frac{1}{9}\)= \(11 \frac{1}{9}\) %